Overunity Device by Tanju Argun (Moderated)

[Tanju]

Well I do not know it yet.  Perhaps a scope shot across the 80V capacitor and an actual schematic on the output parts could shed some further lights on an answer.  And also, a dependable light meter to check lux emitted would also help. Brightness to our eyes can be decisive, unfortunately.

Gyula

I will try to get the scope shot of the 66000 Microfarad smoothing capacitor  tomorrow but I still suspect I will see nothing but a straight line at 80 volts???
Your calculation 300 ma divided by 7 branches equal 43 mA is OK but I dont see the 43 mA on the VI chart of the LED. The chart starts at 200 mA . It is off the chart. How come The LED even lights, My eye is not a  luxmeter of course but I use them in my garden  at night where it is as bright as a football stadium.

[gotoluc]

For those who have problems login in, try this link and let me know if it works any better: http://overunity.com/login/#.WVCRM-srKUk


Luc

[verpies]

LED spec says 28-30 volts and 700 miliamperes. That gives me an internal resistance of  40 ohms. 3 in series is 120 ohms and 7 parallel branches give me an overall internal resistance of 120/7= 17.14 ohms

LEDs do not have a constant resistance. They have a variable resistance that decreases as the voltage across them increases.
Below some threshold voltage, LEDs have almost infinite resistance (i.e. they do not conduct current almost at all).

Take a look at the attached scopeshot.  The yellow trace is a voltage across a single LED and the green trace is the current flowing through the same LED.

The emitted light intensity (luminosity) is proportional to the current - not to the voltage!

I must also mention another peculiar thing which I witnessed.  In the video I have 15 LEDS and my my output current was still 0.3 Amps I later added 2 more parallel branches which brought the LED qty to 21.
And to my surprise the current did not increase. Does this prove that radiant energy "loves" load?

No, it proves that you are driving these LEDs from a constant current source.
Inductors (coils) are constant current sources when they are discharging.

[gyulasun]

Hi Gyula,  I'm guessing you meant "Brightness to our eyes can be deceptive" ?   
....

Yes, I meant and wanted to write 'deceptive', thanks for the correction.
I agree with what you wrote Tanju setup is interesting but needs careful measurements to correctly evaluate its performance.

Gyula

[gyulasun]

I will try to get the scope shot of the 66000 Microfarad smoothing capacitor  tomorrow but I still suspect I will see nothing but a straight line at 80 volts???
Your calculation 300 ma divided by 7 branches equal 43 mA is OK but I dont see the 43 mA on the VI chart of the LED. The chart starts at 200 mA . It is off the chart. How come The LED even lights, My eye is not a  luxmeter of course but I use them in my garden  at night where it is as bright as a football stadium.

Hi Tanju,

Yes, I agree on your seeing a straight line, normally a 66000 uF capacitor is a good filter to smooth out most ripple voltage. If you have already checked this, and confirmed the ripple (if there is any visible) is say less than a few hundred millivolts peak to peak then that is okay it may not cause any surprise riding on the 80 V DC level and you do not need to recheck it. But I do not know whether you already did this that is why I mentioned. Perhaps this check would bring more interesting results in case of the 10 or 20 Ohm resistor load across the 66000 uF.

I also agree that 43 mA is off the chart but I do not know whether your actual LEDs exactly corresponds to that LED type the PDF file data sheet Itsu found? You mentioned the tighter 28-30 V forward voltage range as the difference, that is all. The best would be to check DC current in some of the LED branches out of the 7 to see the actual values whether the 43 mA is reality?

Thanks,
Gyula