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Overunity Machines Forum



Confirmation of OU devices and claims

Started by tinman, November 10, 2017, 10:53:19 AM

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0 Members and 9 Guests are viewing this topic.

AlienGrey

Dave (weetabix) whatever, what your missing like many others is explained by many on a lot of the Lithuanian threads
I can't point to any, I'm sick of it all truth be told but it is simple when you realise current is really a magnetic force like a dynamo,
then you have to stick your nano bemf pulse where it need be.

Gyula bemf that's the trick Smith won't talk about but bring in the current (magnetic flux) and it's gone.
PS all you need to measure magnetic flux is a hall chip a 5v reg and a meter simple

kolbacict

QuoteThe resonance system as the first one or two stages of the "DS system" have failed, it has not been proved to give
"energy multiplication".  Correct measurements by Itsu clearly resulted in underunity while Rick F or benfr clearly claimed
COP > 1 performance for the resonance system. 
And by the quadratic dependence of the magnetic field energy on the current?  W=I^2L/2                   We have two identical coils on the same core connected in parallel. We supply current through them. When all the energy of the current goes into the energy of the magnetic field, we switch these coils from a parallel connection to serial ones using an ideal relay. What will happen?

AlienGrey

Quote from: kolbacict on June 06, 2019, 05:06:32 AM
And by the quadratic dependence of the magnetic field energy on the current?  W=I^2L/2                   We have two identical coils on the same core connected in parallel. We supply current through them. When all the energy of the current goes into the energy of the magnetic field, we switch these coils from a parallel connection to serial ones using an ideal relay. What will happen?
you would lose it into the environment like an aerial works.

kolbacict

But in an oscillating circuit, for example, all the energy of the magnetic field (well, almost all, except for the loss  :( ) goes back into the current, and then into the charge of the capacitor. And so many times. Nowhere is it dissipated in the air.  ;)

AlienGrey

Quote from: kolbacict on June 06, 2019, 06:44:39 AM
But in an oscillating circuit, for example, all the energy of the magnetic field (well, almost all, except for the loss  :( ) goes back into the current, and then into the charge of the capacitor. And so many times. Nowhere is it dissipated in the air.  ;)
Tesla used a cap a bemf coil and a cap and a bar to loop in a circle so as no dc current loop.
work out how that worked a 'hair pin' circuit