12 times more output than input, dual mechanical oscillation system !

[fritz]

In the end the existence of female joggers proves that coupled oscillations are not OU - and no work is performed on movement of oscillating mass.
Otherwise it would hurt like hell. 

[i_ron]

From Wikipedia, the free encyclopedia


A strain gauge (alternatively: strain gage) is a device used to measure the strain of an object. Invented by Edward E. Simmons and Arthur C. Ruge in 1938, the most common type of strain gauge consists of an insulating flexible backing which supports a metallic foil pattern. The gauge is attached to the object by a suitable adhesive, such as cyanoacrylate.

As the object is deformed, the foil is deformed, causing its electrical resistance to change. This resistance change, usually measured using a Wheatstone bridge, is related to the strain by the quantity known as the gauge factor.

This deformation stores the energy applied and acts like a spring. This energy has to be released somehow for the guage to be able to reset. In your setup this energy is fed back into the system and therefore cannot be considered output or work done.

Hans von Lieven

Hans,

I am well aware how strain gauges operate. But you know very well that ‘work done’ is the displacement of a mass. That is, the mass/weight has to be displaced over a distance.

The distance that the mass is displaced in a strain gauge load cell is a minute distance, therefore little or no work can be said to have been done in the gauge. The idea that the gauge absorbs and then releases all the work, as observed in the experiment, and thus negates the experiment, is absurd. Further, the strain gauge load cell is calibrated before use to eliminate any tiny error that may have arisen from that quarter.

Ron

[i_ron]

This deformation stores the energy applied and acts like a spring. This energy has to be released somehow for the guage to be able to reset. In your setup this energy is fed back into the system and therefore cannot be considered output or work done.

Hans von Lieven

Take a pound of butter and place it slowly on a kitchen spring scale. Observe that it weighs one pound. At no time does the spring scale make it weigh any less or any more.

Now have this same pound of butter drop onto the scale. If you are quick then you could estimate that the butter weighed 1 ¼ pounds; but only an estimate because the mass of the scale platform and the fact that the resistance of the spring travel was actually slowing down the butter in its final moments, leads to certain inaccuracies.

How to achieve greater accuracy? Reduce the mass of the scale platform to practically zero and the distance that the falling mass was allowed to travel to practically zero, in its recorded arrest. Voila, a strain gauge load cell.

But does a spring necessarily negate force measurements? No. Take the act of bungee jumping, the force of gravity is known, the persons weight is known and the resilience of the chords is known, to such accuracy that the person can have just his forehead touch the water. One could easily work backwards by observing the stopping point and from that, deduce the person’s weight.

So even If I had used a bungee chord to do my experiment it would not be invalidated on the grounds that it was a spring.

Ron

[hansvonlieven]

Do the following experiment. Just suspend a pendulum from the strain guage and let go. You will get the same sort of readings. You cannot tell me the pendulum is doing work.

Hans von Lieven

[i_ron]

Do the following experiment. Just suspend a pendulum from the strain guage and let go. You will get the same sort of readings. You cannot tell me the pendulum is doing work.

Hans von Lieven

I never said that setup did

Ron