12 times more output than input, dual mechanical oscillation system !

[Omnibus]

To be OU a machine [already constructed] must restore its Potential Energy - if that is an oscillating device that means achieving the same or better starting height for CoM.

If that is a rotating system then the device must restore full Pe of Position & if excess Energy is available it will also manifest as excess momentum & Ke seen as excess velocity as it completes a cycle - so the conditions to be OU is that Pe is restored & to do Work there must also be excess momentum after one cycle.

Non of your examples did this, therefore NOT OU !

These are wrong criteria for a machine to be OU. These criteria are wrong because they are restrictive â€" restoration of the potential energy is not a necessary condition for a machine to be OU. A given potential energy may be converted into other kinds of energies at which additional portion of energies other than potential energy can be produced out of no pre-existing energy source. Thus, smot for known reasons showing disbalance of the overall output vs. input energies is OU, magnetic propulsor also for such known reasons is an OU device etc. OU system is also this: http://www.youtube.com/watch?v=KnqXJbwpNRo because the magnet sphere pulled apart along different routes ends up on different potential surfaces at zero magnetic force (cf. the figure below). Thus, the integral of force along the closed L-M-K-L loop is non-zero.

[fletcher]

No, it's you who needs to learn. Where's the proof that there's no OU in http://www.youtube.com/watch?v=ENrMwPNt9Cc&feature=player_embedded# ?

omnibus .. your talent to ego ratio is out of kilter.

Take another look at the vids - study them instead of what you're going to say next.

But, on the brighter side, your level of incompetence comes shining thru yet again in your posts !

[Omnibus]

In the case at hand, the contention is that the mgdeltaH is the gravitational potential energy which not only helps to complete the first turn but also drives the wheel throughout an entire second turn and allows it to almost complete a third turn. That isn’t at all evident and if someone insists that such speculation is viable one has to prove it quantitatively.

[Omnibus]

omnibus .. your talent to ego ratio is out of kilter.

Take another look at the vids - study them instead of what you're going to say next.

But, on the brighter side, your level of incompetence comes shining thru yet again in your posts !

Quite the contrary, it's your level of incompetence that shines through your posts. Your narrow definitions and limited understanding of the matter proves it.

[Omnibus]

Now, because when the weight attached directly to the periphery only causes one incomplete turn we’ll subtract it from what we see in the vid. So, that mgdeltaH causes the generation of kinetic energy through two complete turns. Think about it. Is that disproportionate or what?