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Overunity Machines Forum



Kapanadze and other FE discussion

Started by stivep, May 26, 2018, 01:48:55 PM

Previous topic - Next topic

0 Members and 40 Guests are viewing this topic.

bistander

Quote from: rakarskiy on June 26, 2023, 03:18:12 PM
Wow! So you don't even know basic things? 
10.4 volts is the voltage on the voltmeter or the effective voltage of the circuit. 
3 ohms - resistor + 1 ohm winding and circuit = 4 ohms;
1.3A is the ammeter reading.
1.3A*4 Ohms = 5.2V is the level of Voltage Drop; 
10.4V + 5.2V = 15.6V is the effective value of EMF under electromagnetic induction.


I = (E-U)/(R+r) = (15.6V-10.4V)/(3+1)=  1.3A

;) Don't embarrass yourself.

I rest my case.

rakarskiy

According to Ohm's law, in the section of the conductor with active res istance R, the current I creates a voltage drop Ui = IR.
;) ;D

PS
the voltage drop level - [Ui], can be determined from the difference of the EMF -[E] and  the effective voltage in the network;  which is shown by the voltmeter - [Ui = E - U]

In blue I added a post on how to check the voltage drop level in the circuit
 

bistander

Quote from: rakarskiy on June 26, 2023, 04:27:17 PM
According to Ohm's law, in the section of the conductor with active res istance R, the current I creates a voltage drop U = IR.
;) ;D

And that is not what is shown. You show 10.4V.
bi

*assuming ammeter shunt is a typical 0.1-0.01 milliohm and therefore negligible.

rakarskiy

The question is, what kind of education do you have? God forbid such a teacher would teach physics to my grandchildren, I would have made a scandal and demanded an aptitude test.


Sergh

About:
https://rakatskiy.blogspot.com/p/ampere-force.html
Looks like a measurement error.

Reading Wiki:

https://en.wikipedia.org/wiki/Amplitude

Rakarskiy probably measured the peak-to-peak amplitude with an oscilloscope. This is (2) "Peak-to-peak amplitude" at the Wiki link.
And it was necessary to divide it by 2 to get parameter (1) "Peak amplitude". Then parameter (1)"Peak amplitude" must be divided by the root of 2 to get parameter (3) "Root mean square amplitude".
Use parameter (3)"Root mean square amplitude" for your further calculations and conclusions. This is true only for sinusoidal voltage!

Wrong measurements lead to wrong conclusions.

Quote from: rakarskiy on June 26, 2023, 04:46:22 PM
The question is, what kind of education do you have?

<facepalm>