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Deformation of the recipient and of the shapes inside it

Started by activ25, August 20, 2018, 04:04:51 PM

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activ25

The device is under gravity. There is water in the recipient. The recipient is deformed from a parallepiped to a square, so the surface is kept constant. During the deformation the water keep constant it altitude: don't lost/give a potential energy. The rotation of the lateral walls costs/needs nothing. The deformation of the white shape (with air inside or in polystyren) gives no energy from the pressure of water but the force from the white shape below gives another force. Even the white shape don't change its altitude, each shape is compressed from the other white shapes.

Low-Q

Quote from: activ25 on August 20, 2018, 04:04:51 PM
The device is under gravity. There is water in the recipient. The recipient is deformed from a parallepiped to a square, so the surface is kept constant. During the deformation the water keep constant it altitude: don't lost/give a potential energy. The rotation of the lateral walls costs/needs nothing. The deformation of the white shape (with air inside or in polystyren) gives no energy from the pressure of water but the force from the white shape below gives another force. Even the white shape don't change its altitude, each shape is compressed from the other white shapes.
If you post a picture instead, more people would open it. A 116kb zip-file with a single letter name, is not considered safe to open.
Just thoughts.


Vidar