Zero and Q device

[v8karlo]

V8Karlo claimed this about his 'Q Device':  "Most of the output energy is returned to source."

In J device ALL the energy from transformer in both phases is returned to source simply
because there is no other way for energy to go. The feedback loop is the only path
for current to flow. J circuit has limitation. Output is half (1/2) voltage from input.
Because of that I moved to Q topology.

Goal is to make Q which returns energy to source in both phases like J and then
ALL of the energy will be returned to source just like in J.

My apologies for that claim because right now Q is returning energy only in
one phase and your observation is true.

[Jeg]

If Karlos doesn't mind, i'd like to attach here one more circuit of the same way of thinking. It is for the experimenters. The waveform of the returned energy back to the source, was attached at the Kapanadje thread before few days. If A.G likes to bring it here it would be appreciated.

I don't recommend anyone to build it from scratch. It is just for showing you here that if potential become higher than input then a good portion of energy can return back to the source and raising this way the efficiency.
All coils 1:1

[v8karlo]

   It seams that what Karlo wanted is for someone to build his circuit

   Will the real OU device, please stand up...

I made my research open source so everyone interested can build that circuits.

I didn't demand for you to build them. It is your choice (open source project).
The other thing is that circuits are so simple and can be build in 1 hour or less.
Nobody can tell that he spends weeks or months to build it.

J device is 2 diodes and 2 capacitors!! Lot of guys here already has some push pull
converter, transformer from before.

I did not make self runner.
I am still on that path to do it.
And that path is called researching and experimenting and developing.

[Jeg]

When left branch conducts, C1 is getting charged together with C2. A secondary in the middle will fire when left branch goes off, and the returned pulse is consumed across the right branch. If the same trick is applied also to the right branch, then C charges up to distraction. Still in progress.

[v8karlo]

Currently I am on Q topology, trying to find how to feedback
energy from both phases to source.