A SIMPLE ELECTRIC HEATER, WHICH HAS EFFICIENCY GREATER THAN 1

tinu · May 09, 2019, 05:38:09 AM

Hi George,

1. Yes
2. Yes
3. Yes
4. Yes, R=0.77 Ohm. This value is the equivalent resistance of liquid resistor DURING electrolysis only!
5. Vps=1V. No electrolysis is taking place. All power delivered by the power supply goes into Joule heating of electrolyte. Ips is unknown because R is unknown. In this regime R is not 0.77 Ohm but larger. Consequently, Ips=Vps/R. Surelly, 0<Ips<<1V/0.77Ohm. Ips can, of course, be easily measured.
6. Vps=1.23V. Still in Ohmic regime, while no electrolysis is taking place yet. All power delivered by the power supply goes into Joule heating of electrolyte. Ips is still unknown because R is unknown. Nonetheless, raising Vps further beyond 1.23V will start the electrolysis. This is a transient phenomenon, characterized by a relatively sharp increase in Ips because the equivalent resistance of liquid resistor (R) is dropping significantly due to an increase of ions concentration. However, it might be necessary to increase the voltage sufficiently high, until H2 and O2 will start forming bubbles, degassing out of the electrolyte and ensuring a stable regime for the electrodes. When full electrolysis kicks in, R is lowered to 0.77Ohm and Ips stabilizes at 1A.

Read carefully: I'm not here to answer your questions! Neither one of the members is. Now, having said that, the above small physics lesson is a favor I did for you. I won't do it again because on one hand, like I said, I'm on holiday and my vacation is rare and valuable and, on the other hand, this is basic knowledge and subject to bellow college-level class experiments. I'm well beyond that and you make me waste my time.
So, in conclusion:
(1). Please do your own experiments, publish the results here and then we can talk further, based on your actual data.
(2). Better yet, please bring in your leading scientist for further theoretical and practical discussions.

Again, please answer to the former question of mine:
(3). What is your formal training and expertise in the field?
(4). Where are you from?

We'll be hearing again when you fulfill (1)-(4).
In the meanwhile, please refrain yourself from posting invectives, fantasies and/or physical non-sense/absurdities, ok?

Regards.

George1 · May 09, 2019, 08:52:46 AM

Hi tinu,
I am already absolutely clear on the fact that you are (a) either an arrogant and ambitious ignoramus, whose expertise in electric engineering is equal to zero, or (b) an unskillful and clumsy manipulator, who is an agent of the BIG OIL (or other similar organization) and who tries to convince us that black is white. I will not waste my time any more (as well as the time of my team's colleagues) to answer your nonsense posts.
George

lancaIV · May 09, 2019, 10:05:55 AM

Dear George1,I am very sorry but have to deny : I am not an expert in physics, only an user.

I wish you fortune and success
wmbr
OCWL

George1 · May 10, 2019, 02:26:57 AM

Hi lancaIV,
Thank you for wishing us fortune and success. And thank you for your good will and patience. I will keep you informed what happens.
Regards,
George

lancaIV · May 11, 2019, 05:11:40 AM

Hey George1,
probably you and some team members read this works and results and discuss about it :

http://guns.connect.fi/innoplaza/energy/story/Kanarev/
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https://worldwide.espacenet.com/publicationDetails/biblio?CC=DE&NR=2733719A1&KC=A1&FT=D#
Compensation of magnetical ( attraction,repulsion)force

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https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=1&ND=3&adjacent=true&locale=en_EP&FT=D&date=20121011&CC=US&NR=2012256422A1&KC=A1#
Above [ 0092,0093,0094]. related :
For example : when a nominal 1000 W and 1000 RPM generator by100 RPM only generates 1W,

100 RPM to 1000 RPM : ten times higher velocity ~ thousand times more power

how many Watts consumes a coupled motor to achieve this 100 RPM ?!
A. Continuous DC power motor B. Fractional AC pulse power motor