Color's Kapanadze forum, FE builds circuits and comments

[AlienGrey]

How to make High Voltage    https://www.youtube.com/watch?v=SO4cIGiYtio

[color]

AlienGrey:

There are a lot of people who write here to interfere with free generator discussions rather than creating free generators.
If you respond to them individually, you lose your purpose and wander.
It is a pity.
 
Free energy technology is very simple.
Many people just do not understand it.

[color]

Only 'if' we could walk on water, , if you remove the input power the power at the secondary will also disappear.
===============


When the push-pull primary coil forms a wave, the secondary coil (grenade coil) acts passively.
The wave of the push-pull secondary coil (grenade coil) comes along the wave of the primary coil.
In order for the push-pull secondary coil (grenade coil) to react to the primary coil wave, a kacher secondary coil must be connected to the secondary coil (grenade coil).
 
Push-pull primary coil, secondary coil (grenade coil), kacher secondary coil.
Excess energy occurs in trinity combinations.

The secondary winding of the yoke transformer should always have excess energy available.
The excess energy of the secondary transformer of the yoke transformer is weak in that state.
 This is because the imbalance formed by the kacher secondary coil is weak.
 There is a limit on the amount of catcher current that Minwell can make and the amount of current that is distributed by the push-pull and yoke transformers.
I have not experimented with power supplies larger than Minwell,
I do not know the amount of excess energy that can be produced with a larger capacity power supply than with Minwell.

If the grenade coil and ground are connected, no excess energy is generated.
When the kacher secondary coil is connected to ground, excess energy is not generated.
Ground is the place to get excess energy, but it is also where it gets released.
 
For example,
To pull up the water with the vacuum pump, there must be a vacuum holding area in the pump.
If there is no vacuum tank, water can not be extracted.

Likewise,
The yoke transformer secondary and grenade coils must remain charge unbalanced (vacuum).
At this time, the diode bridge serves as a valve to maintain the electric vacuum (unbalanced) state of the grenade coil.

https://www.youtube.com/watch?v=t0W1j011-68

And
I hope to reveal the secret of the wave before the retired professor of the video above dies.
  
Now that he has enjoyed his own joy by concealing a very simple secret over the past few years, I hope to give everyone joy.


https://www.youtube.com/watch?v=IZRCIjMWRLg

But
If you burn all the secrets of the free generator with lightning like Master Yoda and disappear .......?

[Jeg]

Hi Color
Very inspiring direction my friend. Thanks for sharing your idea. This unbalance as a reason for sucking energy looks at least interesting. I just wonder what is going on with systems that don't use ground. Do they suck energy coupling to it by an antenna? In any case, I looked again all your posted circuits and indeed they are according with your description above which by the way took me enough time to decode it. I'll try to apply your point of view to my ''imposition'' push pulls.       

Regards

[color]

Jeg:

https://2.bp.blogspot.com/-GkN3WYHkFqQ/XDZf23Jui3I/AAAAAAAAAxI/kPG1Ms894NUy79gFb-OpHkDfvNgz-nFbwCKgBGAs/s1600/%25ED%2598%25B886.gif

https://thumbs.gfycat.com/HospitableTameBongo-size_restricted.gif

위 영상에서 불균형의 음전하 번개가 접지와 접촉하는 부분은 2차원의 평면으로 만난다.

구름에서 발생한 음전하는 코일 역활을 하며 접지와 평면으로 접촉한다.

그래서 양전하가 음전하 줄기를 타고 전기적 평형된다.
전선에서 만나면 + ㅡ가 만나는 합선이다.
위험한 전기 합선을 사용하는 것이 루슬란의 자유발전기 방식이다.

그래서
교류를 직류로 바꿀 때 다이오드는 양전하와 음전하를 분리해서 통과 시킨다.

구름에서 발생한 번개는 음전하를 띤다.

음전하는 다이오드를 통과하 때 + ▼극으로 간다.
접지의 양전하는 다이오드를 통과할 때 ㅡ ▲극으로 간다.

그러니까,
구름에서 발생한 음전하는 다이오드를 통과해서 접지로 내려간다.
kacher에서 발생한 고전압에 음전하가 존재한다.
kacher에서 발생한 음전하는 다이오드를 통과해서 접지로 간다.

kacher가 직접 접지와 접촉하지 않아도 접지에서 양전하를 뽑아낸다.
그리고 다이오드는 수류탄과 접지를 전기적으로 차단한다.

나는 실험을 안해봐서 모른다.
나는 다만 추측할 뿐이다.

누군가가 이런 실험을 해봐야 증명될 것이다.
https://www.youtube.com/watch?v=S_URR6Bk9cg

kacher를 만들고, 접지선에 다이오드를 연결해서 위 실험 같이 펄스가 발생하면 증명된다.

쉽지만 아무도 실험하지 않는다.


In the above image, the portion of the unbalanced negative charge lightning that comes into contact with the ground meets as a two-dimensional plane.

The negative charge generated in the cloud acts as a coil and contacts the ground plane.

So the positive charge is electrically balanced by the negative charge.
When you meet at the front, + ㅡ is the shortest encounter.
The use of hazardous electrical shorts is Ruslan's free generator method.

so
When converting an alternating current to a direct current, the diode separates positive and negative charges and passes them through.

Lightning from clouds is negatively charged.

Negative charge goes to the + polarity when passing through the diode.
The positive charge on the ground goes to the pole when it passes through the diode.

So,
Negative charge from the cloud passes through the diode and goes down to ground.
There is a negative charge at the high voltage developed in the kacher.
The negative charge generated by the kacher goes through the diode to ground.

Even if the kacher does not contact the ground directly, it draws the positive charge from the ground.
And the diode electrically isolates the grenade and ground.

I do not know the experiment.
I just guess.

Someone will be able to prove it by doing such an experiment.
https://www.youtube.com/watch?v=S_URR6Bk9cg

A kacher is created, and a diode is connected to the ground line.

It is easy, but nobody is experimenting.