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Overunity Machines Forum



REAL CAPTRET CIRCUIT

Started by Mancha, March 21, 2019, 08:12:05 AM

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conradelektro

Quote from: Mancha on March 21, 2019, 04:17:19 PM
Hello Conrad,
Do not need to destroy capacitor as everybody is doing, also it gives  option to chose different size of capacitance and explore other option.
But major point to  understand circuit.
Best,
Mancha


Sorry, I do not understand what you mean. Maybe, we both do not understand English well enough.


Conrad

gyulasun

Quote from: Mancha on March 21, 2019, 08:12:05 AM
Hi,
This is real captret circuit. Two capacitoirs in series connected parallel to another bigger capacitance .
the source of captret is capacitor C2 which will receive opposite polarity of charge and it is problem for  C2.
Hi Milan,

Nice to see you back.  As I see your circuit, approaching it from the battery point of view, C2 is directly in parallel with the battery but with reverse polarity and as you wrote this is a problem for it. C1 which seems also to receive reverse polarity is in series with C3 and these two series capacitors are also in parallel with the battery (hence with C2 too, of course).

Because I have not understood the real role of a captret, I cannot see the purpose of this circuit either. I think you wish to communicate something here so please explain. 

Greetings
Gyula

F6FLT


From what I deduce from JL Naudin's experiments on the captret, a chemical capacitor is used as a battery cell. The two electrodes are the case of the capacitor and the negative electrode. The electrolyte of the capacitor plays the role of the electrolyte of this battery cell.
Raising the voltage of the main battery at the beginning of the experiment is intriguing, as the difference exceeds the voltage that a single cell can provide. An explanation is missing.
However JL Naudin showed that it is not overunity, the battery eventually discharges as the chemical energy of the capacitor used as a battery is consumed.

Mancha

For Conradelektro and Gyulasun
What I tried to say that there is no need to destroy capacitor to build captret. the same  results you can get with circuit. 
All the best,
Mancha

Mancha

Hi  F6FLT
For me is mystery how 9V batteries got charges across LED in non conductive direction.
Best,
Mancha