Nelson Rocha Workbench

[Magluvin]

Thank you.

Let's say we have a large source of DC potential, a switch and a long wire in series connected to the positive terminal. Let's say the negative of our source is connected to ground. At the moment of switch closure, before charges start to move, the voltage appears across the conductor even at the very end.... The electrons take time to begin moving, but at the other end of a connected wire a voltage appears. Let's say our wire is floating. It is not connected to anything at the other end. Throughout all space that wire occupies an electric field appears, also instantaneously. It doesn't matter whether any current flow occurs, this field appears. We can open the switch, the field decays. Let's say our wire is an open circuit with several GOhms between the wire and the ground - how much current flowed? Almost none.

We reordered the vacuum and it cost us nothing. We changed something, created a small ripple in the electromagnetic pond, but we spent nothing provided no charges moved.

If your meter is connected to measure the voltage, then your meter is the load, and a very high ohm load compared to the connecting wire you speak of. So current flows(very little to get the meter to read) when your meter(load) is connected to the circuit.
Mags

[voltaicfractal]

If your meter is connected to measure the voltage, then your meter is the load, and a very high ohm load compared to the connecting wire you speak of. So current flows(very little to get the meter to read) when your meter(load) is connected to the circuit.
Mags

I believe you mean your meter. Since you introduced the meter, it must be yours.

[nelsonrochaa]

Thank you.

Let's say we have a large source of DC potential, a switch and a long wire in series connected to the positive terminal. Let's say the negative of our source is connected to ground. At the moment of switch closure, before charges start to move, the voltage appears across the conductor even at the very end.... The electrons take time to begin moving, but at the other end of a connected wire a voltage appears. Let's say our wire is floating. It is not connected to anything at the other end. Throughout all space that wire occupies an electric field appears, also instantaneously. It doesn't matter whether any current flow occurs, this field appears. We can open the switch, the field decays. Our wire is an open circuit with several GOhms between the wire and the ground - how much current flowed? Almost none.

We reordered the vacuum and it cost us nothing. We changed something, created a small ripple in the electromagnetic pond, but we spent nothing provided no charges moved.

Hi voltaicfractal,

Regarding the example given:
with one end of the conductive wire connected and the other suspended in the air,
the current will depend on the surface size of the unconnected wire conductor and the distance relative to ground and their surface size, where also need to be considered, the dielectric element (air) between the plates , resuming It will behave like a condenser.
Knowing this distance between plates , the electric field can theoretically be calculated using mathematical formulas as well the displacement current however is relevant say that it is not an electric current of moving charges, but a time-varying electric field.

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Nelson Rocha

[nelsonrochaa]

I believe you mean your meter. Since you introduced the meter, it must be yours.

voltaicfractal,
Sincerely i feel some hostility in your answer to Magluvin ,and besides being unnecessary, it does not add anything positive to the theme we are talking. I would like common sense and tolerance prevail among the participants in this topic, because as i mentioned earlier, in the difficult times we are in, respect and tolerance are points of order.
Thank you for your understanding.

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Nelson Rocha

[nelsonrochaa]

If your meter is connected to measure the voltage, then your meter is the load, and a very high ohm load compared to the connecting wire you speak of. So current flows(very little to get the meter to read) when your meter(load) is connected to the circuit.
Mags

Magluvin ,
Hope you goes well ,
I think personally the example you used is not the best to illustrate what we are talking  , because we are talking in hypothetical displacements currents present relative ground and other point of wire disconnected.
Being displacements currents not an electric current of moving charges, but a time-varying electric field, in my perspective  the example you give not apply because  is different of conduction current, in the conventional electrically conductive means.
I leave a patent link for a device for measuring current displacements that seems very interesting so that you might be interested.
https://patentimages.storage.googleapis.com/73/6d/ac/0d8caf02f855e9/US4224540.pdf

Best rewards

Nelson Rocha