Lords of the Ring

[Motorcoach1]

 Personialy I not into the Ion thing I looked at the circut for the capacitor ram multiplyer - part of it found that to be interesting

[giantkiller]

Results on the GKMTC1-EZflow:

I drive top and bottom Helmholtz(hhcoil) with tip41s with 555 for 12 volt out @ 91khz(resonance for my hhcoils) through a 10 ohm resistor on each channel. Thats it.

I see 2.5 volts on the control windings(bobbin type windings of 30awg.),
1.75 volts on the ezflow, scope is across the 2 connections or scope gnd to ckt ground. Wave just looks different.
With scope gnd to ckt gnd I see 2.5 volts on the hhcoil control winding(22awg gold colored winding)
I see 3.25 volts on the original middle collector.
The bemf is in all the windings.
Now when I put an led or a 12volt lamp on the ezflow it does not light but the signal does not degrade either!
When I short the ezflow the signal does not degrade either! No sparks.

@ 88.1khz & 87.7khz I see 4 volts on the orignal midde collector. Excellent spikes and ringing all through out the windings.

The original middle collector is not hooked in any ckt. All windings are seperate.

Coil stays cool.
Compass has a 1/2 degree waver back and forth.

--giantkiller. Back at it tomorrow.

[Bruce_TPU]

Sounds good gk,

and Thanks for the details.  We need that from all the experimenters!

Psalm 150:6
Bruce     

[shuzammy]

@Bruce

Great Petra song.

[Bruce_TPU]

@ gk
I read this and it reminds me of what you are doing with your new ring.  It has some good info, and your ring and this patent have given me a lot to think about how to "collect" those electrons. 

http://www.freepatentsonline.com/20050147544.html

It is a patent for a "portable" ion generator

[0005] Assuming the ionizer is powered by a 9 volt battery and assuming an ideal transformation circuit to generate high voltage, the current drawn from the battery would be inversely proportional to the voltage of the battery. Thus, if the ionizing voltage is 6.times.10.sup.3 volts, the battery current drawn from a 9 volt battery would be 1.times.10.sup.-6.times.(6.times.10.sup.3/9)=0.666 milliamps. Even if one assumes a 50% efficiency for a practical transformer circuit, a battery current of only be 1.33 milliamps would be required to generate 6.28.times.10" ions/sec. Current of this magnitude could be easily accommodated by an ordinary battery, particularly those of the alkaline type.

[0006] In order to generate ions, a region of high field gradient must generally be created. A needle as an emitting electrode helps generate ions because the field gradient at the needle tip is inversely proportional to the radius of the needle tip. However, as well as an emitting electrode, there must also be a counter-electrode to form the requisite electrostatic field. (This made me think of what you have done with your ring...very impressive!!)  The counter-electrode must be connected to an output lead of the high voltage power supply to provide.a current flow through a circuit that includes the ion flow as part of the circuit. Normally this output lead would be grounded to earth through the power source i.e. the grid power outlet or the cigarette lighter socket in a car. But in case of a self-contained unit, there is no readily apparent place for connection of the counter-electrode.

[0007] For ion generators supplied power from the grid or mains, capacitive coupling allows the surrounding earth to serve as a counter-electrode. Being remote, the field is spread out in space and if it were not for the size of the earth, the field gradient at the ion emitting electrode may be modest. Connection of the potential source to a more proximate, explicit electrode will increase the field gradient at the ion emitter tip. As well, a counter-electrode of larger area will increase the efficiency of ion emission by the ion emitter tip

Thank you for your time,
Bruce