Reactive Current - Parallel RCL

[nix85]

I know he is into displacement current and stacked Tesla pancakes, nothing new
or original about that.

Don Smith reported on a Yahoo group in 2006 that using 3 resonant Tesla pancakes
with 14 watt input he literally melted the diode bridge rated at 20,000V and 200A.

That's more than 4 Megawatts.

Again, this claim of IV in phase in the third coil does not hold water.

You can model overunity as negative resistance, that is an old and popular idea.
I read all pdfs from vixra, that is all nice and sweet but that is just an attempt to
conventionally explain what cannot be conventionally explained.

Fact is literal negative resistance is not happening in most OU devices neither is
current flowing in reverse. There is simply an amplification of energy.

According to Dan Combine's pdf from 2006. attached below radiant energy
enters the resonant circuit at voltage nodes as depicted by the red stars.
So there is not necessarily even amplification of current, just, for example,
a 220V 1000W bulb lit fully with 19V across it and 4.5A through it. Bolt also
spoke about this.

[kolbacict]

Accidentally came across a book parametric transformers (parametric power supplies)
I drew attention to the analogy with your circuit (circled by me in red)
.zip]http://publ.lib.ru/ARCHIVES/Z/ZADEREY_Gennadiy_Panteleymonovich/Zaderey_G.P..._Mnogofunkcional'nye_transformatory_v_sredstvah_vtorichnogo_elektropitaniya.(1989).[djv-fax].zip
These were mass-produced power supplies for electronic equipment.
I think it was in other countries too.

[nix85]

From Dan's pdf above.

"Ever read the meaning of resistance and voltage drop in a basic LRC circuit?
At resonance you have 0 voltage at n amperes and x voltage at 0 amperes;
L is in current node; C is in voltage node. Where is R then? According to
the standard theory, R as a lightbulb is in PHASE, but the reality is that R
is at 90% REACTIVE state being at CURRENT node, so the energy loading
e.g. a 220 VAC 1,000W lightbulb might just have a voltage drop of 19V and
amperage of 4.5 A. Why does it light up at full potential then?"

Along similar lines bolt's posts here.

https://overunity.com/9521/magnacoaster-vorktex/

"You have to read back through my posts click my handle and read i published
loads. But here is my AWAKENING tool.  Take a 250 watt light bulb and in series
fit a capacitor and inductor selected so the i/p power is power factor ZERO.
The watts consumed and measured by any suitable test method will show
leakage power around 3 watts when i did this. The 250 watt light is FULLY LIT.
The volts drop across the bulb is about 12 volts. The bulb works underwater
perfectly fully lit. The power factor is virtually zero creates standing wave the
bulb is powered by zero point energy for FREE.

its the basis for many many OU systems."

There is your "secret", there is no secret, it's just reactive power sucking in RE
but it's very delicate and requires precise tuning for best effects.

[alan]

Any replications out there? 
Won't the resistive bulb cause an increase of the PF, or make it more positive on the real axis in the complex plane?

They say in an inductor voltage leads current, but it is the changing current that causes the voltage, mathematically voltage is the derivative of current, cosine is the derivative of sine. at sin(0) the value is 0 but the change is maximum, the cosine plots the  change.  Capacitor is similar, current is caused by a changing voltage, but it is described as current leads voltage.
But that's all basic stuff that most people here know.

[nix85]

Yes, that's basic stuff all know but a good point and i've been thinking about that lately.

Indeed, voltage across an inductor appears due to change in current, so technically
there has to be some current FIRST before back EMF jumps to supply voltage value
and blocks sudden rise to full current. And exactly the same things happens for voltage
in a cap indeed, there has to first be a change in voltage across a cap for current
to flow "into" it.

Good place to remind voltage across transformer primary or secondary is

E = 4.44 * number of turns * frequency * flux in the core

But for flux in the core to appear there first has to be current through the coil

This flux is proportional to input voltage and inversely proportional to frequency

E/f