Holcomb Energy Systems:Breakthrough technology to the world

[bistander]

Where did you see a mistake in me?
...

Hi rakarskiy,

*** By the way, the total current should be I = U / R = U / (R + r0) = 10.4 / 4 = 2.6A.

After all this BS, you finally see your mistake.
bi

"current should be ... 2.6A" vs 1.3A on your diagram, copy attached below.

[rakarskiy]

bistander, I'm seriously worried about you!

Did you really understand nothing?
You cannot understand the real indicators (taken by real devices) and the calculated ones, why are they different?

It's hard for me to understand, do you really not understand, or are you playing at misunderstandings on purpose?

[bistander]

bistander, I'm seriously worried about you!

Did you really understand nothing?
You cannot understand the real indicators (taken by real devices) and the calculated ones, why are they different?

It's hard for me to understand, do you really not understand, or are you playing at misunderstandings on purpose?

You show a circuit branch with a 10.4V source, 1.3A and 3 Ohms. How is that not a discrepancy?

real indicators (taken by real devices)

?
Put 10.4V across 3 Ohms and show me 1.3A. You need to get real.

Did you really understand nothing?

I understand electric machinery and circuit analysis and Ohm's Law very well. But I admit that I don't understand you.

Nevermind. I'm through with you. You just throw numbers into any equations, use bad math and post falsehoods all over the place.
bi

[rakarskiy]

Now it is clear! Good luck in your service to the master!
Unlike employees, I am absolutely free and do my job.
Rich would have been surprised to have been told that he had read the instruments incorrectly.

By the way, the material is based on real experiments by two independent testers who understand and make devices on their own.

[Ufopolitics]

You show a circuit branch with a 10.4V source, 1.3A and 3 Ohms. How is that not a discrepancy?
?
Put 10.4V across 3 Ohms and show me 1.3A. You need to get real.

Hello Bistander,

Sorry to get involved here...but I would like some further explanations as understanding.

I have run a Coil with Two(2) Ohms at 12 Volts and have read over 2.0 Amps...on Pulsed and straight DC.

Doesn't it also depends on the Wire Gauge used, plus the number of turns?

I have also ran 36 plus volts on a Coil of 1 ohm, and have over two(2) and 3 Amps...

None of those values above "make up" for the Ohm Law Formula?

Also, isn't the Ohm Law applicable only to straight (not pulsed) DC Circuits?

On AC, does Ohm Law works as well?

Thanks in advance for your answer(s)


Ufopolitics