Vapor Carburetor Series

[TommeyReed]

Hello All,

I'm doing a series on vapor carburetors and other technology to get the most fuel efficiency for every engine.

https://www.youtube.com/watch?v=1tsVmwFHxwE


Tom

[ramset]

Sir
Thank you for revisiting this , it seems there is definitely something to learn here !


And our planet desperately needs alternatives while we transition !


I have heard water or water mist ( perhaps you have mentioned this ) needs more investigation in ICE ( internal combustion engine) applications!


Thanks for sharing
Respectfully
Chet K
Edit (this edit was done after Floor comment below
Ps
I had very recently (yesterday) heard through an associate of ours
That a man has run "ICE " on 1% fuel and 99%water /atmosphere
And (this is not idling for brief periods) At power_ "while driving"!
Tom,
I know if any of this is true , you are definitely the guy to do it here ( at this time ) !

[Floor]

Agree...

yes please
and
thank you !

[truesearch]

@TommyReed


I'm looking forward to what you have to share on this topic.

Related to it I found the following article interesting ~ especially the claim that "carb" engine produced more power than an "EFI" engine:
https://www.autoevolution.com/news/why-carburetors-are-making-a-comeback-178386.html

[TommeyReed]

Hello all,
I did some research on gasoline expansion.

How much does 1 gallon of gasoline displace as a vapor?
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Wiki User
∙ 12y ago
Best Answer
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Briefly, the saturated vapor volume of an average gallon of liquid gasoline when fully evaporated is 160.4 gallons of vapor at 60° F and sea level.

Vapor volume of a liquid is the number of cubic feet of vapor resulting from the complete evaporation of the liquid. The vapor volume depends on parameters of density, temperature, pressure and molecular weight which is affected by the variety of formulas for gasoline that is comprised of a wide range of hydrocarbons.

Several approaches are available to solve this problem. One is shown below.


Using a common industrial formula:

one liquid gallon = [(8.31) x (SG) x (387 cu ft)] / (MW)


Where:

8.31 = pounds in gallon of water

SG = specific gravity of liquid being vaporized

387 = At standard conditions, one pound-molecular weight of a material will evaporate to fill 387 cubic feet of space.

MW= molecular weight of liquid being vaporized


Then using the approximate gasoline constants:

one liquid gallon of gasoline = [(8.31 pounds in a gallon of water) x (.70 approx. specific gravity of gasoline) x (387 cu ft)] / (105 molecular weight of average gasoline)

= 21.4 cubic feet of vapor volume


There is 7.481 U.S. gallons in one cubic foot.

So:

one liquid gallon of gasoline = (21.4 cubic feet) x (7.481)

= 160.4 gallons of saturated gasoline vapor


The vapor volume will vary based on the specific formulation of gasoline, pressure, and temperature.

D. Hollatz
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Wiki User
∙ 12y ago
Is this answer is for liquid gasoline to vapor 1:160?