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Donut sealed pontoon system

Started by panyuming, May 05, 2023, 12:14:50 PM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

panyuming

Quote from: Willy on May 14, 2023, 07:36:33 AM
A very nice study in buoyancy, I think.

Thank you Willy for joining the discussion.

The mass (weight) of each pontoon's own structure is the same.
There are as many pontoon skewers on the left as there are pontoon skewers on the right.
They are balanced to the sprocket center.
So just calculate the difference in the number of pontoons on the left and right sides in the water,
and then calculate the volume of air in the pontoon of the difference,
and the buoyancy value is obtained.

So buoyancy has nothing to do with the mass of the pontoon.

The force required to pull the pontoon down from the sealing ring is divided into two parts.
one Part is the upward buoyancy of the water on the bottom surface of the pontoon.
This force is roughly balanced by subtracting the buoyancy of one pontoon on the left.
The fatal mistake I designed could be here. ;)

The other part is the friction of the pontoon with the sealing ring.
This friction force is mainly related to the difference between
the hole diameter of the sealing ring and the interference fit of the pontoon diameter,
the material elasticity of the sealing ring,
the lubrication between the sealing ring and the pontoon,
The number of layers of the seal,
and the pressure of the water depth.

Minimize the interference fit between the sealing ring and the pontoon,
minimize the number of layers of the sealing ring,
and try to use materials with good elasticity, which minimizes these frictions.

The total effect: the rate at which water leaks from the bottom of the seal
into the air pipe is lower than the speed at which the pontoon
carries water out of the air pipe at the rated operating speed.
It works well.

I won't calculate any of that. :(  :-[
I just feel that it can be done, the friction is less than the buoyancy of one pontoon.
So I put the total loss at 37%, which should have margin.

I used to think that buoyancy machines would get a lot of buoyancy.
After roughly calculating this machine, I don't think it's worth actually making.
Because the output/size ratio is too small.
Probably because the speed that can be achieved is not high.
The higher the operating speed of the pontoon, the greater the output, and the smaller the effective buoyancy.

Although this buoyancy machine may be a free energy device.
But it is not as practical as using solar panels or wind turbines plus battery systems.

Thank you!

panyuming

According to
https://overunity.com/19459/buoyancy-calculations-making-use-of-an-exception-to-archimedes-principle/21/
Site case Fb

The buoyancy of each pontoon is caused by the difference in water pressure between the bottom and top surfaces.
The pressure difference between the bottom and top surfaces of the pontoon
coming out of the sealing ring on the right may be equal to the sum of the pontoons on the left.

So, my design was wrong and impossible to achieve.
Sorry to delay everyone's time.

Tarsier_79

Quotehe force required to pull the pontoon down from the sealing ring is divided into two parts.
one Part is the upward buoyancy of the water on the bottom surface of the pontoon.
This force is roughly balanced by subtracting the buoyancy of one pontoon on the left.
The fatal mistake I designed could be here. ;)

Correct. The force is the pressure at the depth. It is not countered by the pressure on the top surface of the pontoon, so it will be significantly more. Sorry, but here is no advantage to your design.