Free energy from gravitation using Newtonian Physic

[zerotensor]

pequaide:

It is clear that you do not fully grasp the concept of angular momentum.

The formulae and equations of angular momentum can be derived from their linear counterparts in a straightforward way.  The benefit of using the angular formulation is that one does not have to add up a large number of individual linear momenta.

Let's apply this to the example you gave earlier:

Wrap a string around a 5 kilogram rim mass pulley; suspend a 1 kilogram mass from the string as in a one suspended mass Atwood machine. This is one kilogram accelerating 6 kilograms. Acceleration equals 1/6 * 9.81 m/sec/sec. If you let the mass drop one meter the entire system will be moving 1.808 m/sec.

Only this time, instead of a pulley with all of its mass concentrated on the rim (which is rather unphysical), lets substitute a pulley with a uniform mass distribution.

To proceed as you did in the example, we would have to sum the linear momenta of each infinitessimal mass element, for each ring of mass in the pulley, for the duration of the applied force at the rim.  This can be done, and once the calculus dust settles, you will find that you have obtained the formulation for the behavior of the system in the language of (*horror*) angular momentum.  In fact, that is how we got these equations to begin with.

Instead of going through a process of re-inventing the wheel every time, we notice that a general rule can be applied to these kind of systems.  It turns out that (in the absence of friction and the like), the total angular momentum is conserved.  This makes calculating the behavior of these systems much easier, provided we know or can calculate the distribution of mass in the system.

The systems you cite as exceptions to the rule appear at first glance to violate the conservation law, but upon closer inspection, they all involve varying moments of inertia, and can be modeled perfectly well using the concept of angular momentum.

While there is nothing wrong with using a linear approach to tackling these kind of problems, it is often far easier to use the angular analogs.

Your assertion that angular momentum is not conserved, while linear momentum is conserved demonstrates a deep misunderstanding of the underlying physics:  The conservation law for angular momentum can be directly derived from the linear equations.

Of course, when we venture outside of the bounds of Newtonian physics, these concepts need not apply -- but I don't think we need to resort to relativity or QM or any other theory to model your machine-- good old fashioned classical mechanics will do just fine.

[pequaide]

Well said.

But there is one major problem with angular momentum conservation; it does not work (in the lab). Linear momentum conservation does work, it?s a pragmatic issue.

My text books give me the formula of mr?θ for angular momentum. If I were to calculate the mass (cut to length) of the 4.5 inch coupler from the mass (that is stopped at full extension by the spheres) of the 3.0 inch pipe I would have cut it to: 366g * 3.25in. * 3.25in. * 1 radian/sec = 3865.9;    3865.9 / 4.78 / 4.78 / 1 radian/sec = 169 grams.

At 169 grams for the 4.5 inch I.D. coupler (added to the bottom of the top cylinder) the spheres would not have stopped the combined cylinders exactly at full extension.  The combined cylinder system would have stopped well before full extension of the spheres; and the cylinder would be moving backwards while the string is in the slot.

But the cylinder made a nice clean stop at full extension using the 249 gram length of 4.5 in. I.D. coupler. This is linear Newtonian momentum conservation.

What people assume and what really works are often two different things.

Early physics was founded upon experimentation, now it seems science just assumes everything.

[pequaide]

A pulley can change the direction of a force but it does not change the quantity of force. A 12 newton clockwise tangent force at any position on the circle of the pulley can be balanced with a 12 N counterclockwise tangent force at any position on the circle.  Six 2 newton clockwise tangent forces at any position on the circle can be balanced with a 12 N counterclockwise tangent force at any position on the circle.

A two kilogram mass moving 1 m/sec clockwise in a circle will need two newtons of force to be applied for one second counterclockwise in a tangent direction to get it to stop. The mass can move around the circle as the force is being applied, and the applied force can move around the circle as well because the position of the mass or the position of the applied tangent force is unimportant. Note: that the size of the circle with a center bearing is unimportant, and a balanced wheel could be mounted vertically or horizontally.

This means that a moving wheel can apply its motion to an object in a linear path without loss of motion to the system, and vise versa. 

This means that a massive large diameter moving wheel can apply its motion to a small diameter light wheel without loss of motion to the system. The moving mass of the cylinder in the cylinder and spheres experiment could be contained in the motion of a separate larger wheel; it need not have the same radius as that of the spinning spheres. In fact; linear motion could be used for the moving mass of the cylinder.

The larger wheel or linear motion being used (instead of the same radius that the spheres use) should eliminate the concept of angular momentum conservation. But more importantly it opens a vast array of possible arrangements for the cylinder and spheres experiment, so much so that we might have to call them momentum (linear) consolidation experiments.

So let us review the simplicity of this energy making machine and see if Newtonian Physics has been violated.

A one kilogram mass moving five meters per second collides with a four kilogram mass at rest.  The combination proceeds at 1 meter per second. The combined mass is then caught on the end of a string (of any length) at 90?, the mass will proceed around the circumference of the circle at one meter per second. The circle then acts as a cylinder and spheres experiment and throws all the motion back into one of the five kilograms. If the original motion is to be conserved as Newton would predict the motion must now again be five meter per second.

Momentum is conserved so the event in the proceeding paragraph should sound logical to you, now calculate the energy changes. E = 1/2mv? 

My data confirms Newton?s predictions, and the Law of Conservation of Energy is false.

[spyblue]

Hello pequaide, I?m very impressed with your experiments and knowledgment.. can you send me your experiment video please ?!
my e-mail is felipe.bit@gmail.com I would like if you can add me on msn messenger.. my contact is felipexz@hotmail.com

Congratulations for your great work
Thank you
Felipe

[pequaide]

I think we have narrowed our inability to place video on the internet to DVD formatting problems. I will probably buy a new DVD recorder next week. And one of my constituent uses hotmail so I will ask him about that. Thanks