New accelerating gravity wheel ! Converted video from www.newenergymachine.com !

[noonespecial]

MY question is. Are you fully done with the design or are you still looking for better ways?

Hi AB,
I think Bob may be having problems accessing this site. He sent me an email yesterday to say that he is working on a new way to be able to lift more weight. He didn't go into detail in the email but maybe once its complete he will let us know.
Best regards,
Charlie

[LarryC]

Here's my latest concept drawing based on what we know so far. Bob has confirmed that the cam is fixed and works as I thought from 3:30 to around 5:00 then the lever takes over. Larry, you might be able to modify your design in this way.

May be able to modify. But, where did the arm with the round weights come from, it would have stuck out in the Bob K. pic. I can see how the lever could be hidden in the base.

@Bob, thanks for sharing. We really needed your help with the design. Looking forward to learning when we can order and how much.

Regards, Larry

PS: Unit slowly coming along. Getting ready for Ike.

[noonespecial]

May be able to modify. But, where did the arm with the round weights come from, it would have stuck out in the Bob K. pic. I can see how the lever could be hidden in the base.

@Bob, thanks for sharing. We really needed your help with the design. Looking forward to learning when we can order and how much.

Regards, Larry

PS: Unit slowly coming along. Getting ready for Ike.

Hi Larry,
I was keying off of Bob's previous comment: "To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb (actually 60 but who's counting )plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight."

I don't know if my drawing is correct or not. And you are right that there is no arm sticking out in the video. From what he wrote, we know that there is a 10 pound weight pressing down on the long arm of the lever somewhere to lift the weights. This is the only way that I can envision it. You say that it could be hidden in the base but how would it act like a lever from below?
Best regards,
Charlie

[LarryC]

I was keying off of Bob's previous comment: "To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb (actually 60 but who's counting )plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight."

I don't know if my drawing is correct or not. And you are right that there is no arm sticking out in the video. From what he wrote, we know that there is a 10 pound weight pressing down on the long arm of the lever somewhere to lift the weights. This is the only way that I can envision it. You say that it could be hidden in the base but how would it act like a lever from below?

Actually Charlie, I'm more confused then before Number one is how does the 6 inch section of a lever lift a weight set 8 inches? The second part of that problem is the long end only has one clock position (30 degrees) to move the short end.

About the 36 inch rod discussion, in my last version and Bob K. pic version, the weights moved 24 inches, but with the unusable 1 foot section in the center, the connecting rod was 36 inches. So maybe Bob is talking about a new design with a 25 inch connecting rod.

In your drawing it seems the lever with the pivot and stops are attached to the base. Since Bob K. machine was offset to the left on the base, it seems that the lever could be attached to the base but a little lower.

Your solution is one way, just didn't seem to fit the previous pic. Seems like it would be more of an L shaped lever connected to the backside of the unit, which could remain out of site until pulled. Just can't figure out how to get the distance required.

Not sure if the various 10 lb weight discussions was just a typo or 2 different sets.

@Bob,
Please assist, as we are confused again.

Regards, Larry

[noonespecial]

Actually Charlie, I'm more confused then before Number one is how does the 6 inch section of a lever lift a weight set 8 inches? The second part of that problem is the long end only has one clock position (30 degrees) to move the short end.

Good point! Seems like my previous drawing would work better. So I wonder how he is doing it? In my last email to him I asked specifically how the lever worked but he didn't really say. Just said that he is working on a new way to lift even more weight with a 'super-charger' (his words).

About the 36 inch rod discussion, in my last version and Bob K. pic version, the weights moved 24 inches, but with the unusable 1 foot section in the center, the connecting rod was 36 inches. So maybe Bob is talking about a new design with a 25 inch connecting rod.

Its possible that there is no 'unusable' section in the middle if the weights are mounted and track outside of the end of the center shaft. And what happened to the 2.5" and 10" lever? Perhaps he has completely revamped his design since he wrote before.

In your drawing it seems the lever with the pivot and stops are attached to the base. Since Bob K. machine was offset to the left on the base, it seems that the lever could be attached to the base but a little lower.

Your point is well taken and there must be more to this lever that he is not explaining. His crude drawing of the 36"-----------------cl-----6" also seems to indicate that he is leveraging the weights from left as well.

Your solution is one way, just didn't seem to fit the previous pic. Seems like it would be more of an L shaped lever connected to the backside of the unit, which could remain out of site until pulled. Just can't figure out how to get the distance required.

Agreed. I hope we don't have to wait the additional 12 months before his patent is available before we figure this out .

Not sure if the various 10 lb weight discussions was just a typo or 2 different sets.

This is the part that threw me and why I embarked off on my new incredibly beautiful but hideously wrong drawing... .

@Bob,
Please assist, as we are confused again.

Yes please.
[/quote]

BTW, I was watching the weather and they said that Ike may track more toward Houston so hopefully it will only skirt your area.
Best regards,
Charlie