Chas Campbell free power motor

[Humbugger]

G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

Then why don?t you calculate  the torque arms ?
Where is my error in my calculation ?

Here it is once again:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

Divided by 2 cause only for 30 instead of 60 degres rotation
we still have a 3.9 versus 3.6 advantage.

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

for 2 balls to be on the 4x arm... they would both be at 15 degrees off center..  not one 15 degrees off from each other, were working with a 30 degree seperation from each other, there would be no way for 1 ball to be at 4

2 balls at 3.8 distance from axis x 1 Kg = 7.6   

divide by 2  = 3.6

3.6 = 3.6

I think we wasted 5 pages for that?

@rMuD and Stefan

Nobody understands I guess.  YOU CAN'T GET TWO BALLS ON THE RIGHT SIDE AT ANY TIME IF THE WHEEL IS 4/1 RATIO.  THE BEST YOU WILL HAVE IS ONE; SOMETIMES NONE.

Sleep on it...look at it again tomorrow...I'm not crazy...
http://www.overunity.com/index.php/topic,2487.msg48099.html#msg48099

Guten Nacht,

Humbugger

[zero]

Just in case it was misunderstood,  heres a 3d and side view.

Also, there is the idea of trying to change the angle of decent to
a steeper angle for more power..   And or to give more width to the
unit - thus increasing the time where the ball can generate more
speed.

However, I think its probably best just to keep it 
narrow,  and increase the drop angle.

[Humbugger]

Just in case it was misunderstood,  heres a 3d and side view.

Also, there is the idea of trying to change the angle of decent to
a steeper angle for more power..   And or to give more width to the
unit - thus increasing the time where the ball can generate more
speed.

However, I think its probably best just to keep it 
narrow,  and increase the drop angle.

I am guessing you are a stubborn enough optimist that you will have to build it (maybe several times) to prove to yourself it does not work.  Oh well!  You're in the right place for that kind of thinking.  It's the norm here.  Best of luck to you.  I'm old and haven't that much time on my hands, so I'm probably just a wee bit jealous of the luxury.

Humbugger

[rMuD]

G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

Then why don?t you calculate  the torque arms ?
Where is my error in my calculation ?

Here it is once again:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

Divided by 2 cause only for 30 instead of 60 degres rotation
we still have a 3.9 versus 3.6 advantage.

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

for 2 balls to be on the 4x arm... they would both be at 15 degrees off center..  not one 15 degrees off from each other, were working with a 30 degree seperation from each other, there would be no way for 1 ball to be at 4

2 balls at 3.8 distance from axis x 1 Kg = 7.6   

divide by 2  = 3.6

3.6 = 3.6

I think we wasted 5 pages for that?

so it 's really 3.8, but it's not

at 3.8763x the size is 30 degrees  4:1 is less than 30 degrees

there are never more than 1 ball in the system  + the > 10% of the time there is a -3.6 

3.6 :  1.64

if we did balls every 15 degree it would be around 7.0 : 3.9 (guess)

[Humbugger]

rMuD hurrah!  I knew you'd gotten it!  Thank you! 

Maybe our fearless but sleep-deprived moderator will see it all in his dreams...

At anything above 3.8763, the lower ball is off the wheel BEFORE the upper ball comes on the wheel!  


ok...I guess I'm off to whip the children, kick the dog, beat the wife, smoke a hemp cigar, get drunk and get arrested...all is well...someone gets it!


 

Humbugger