Chas Campbell free power motor

[rMuD]

Okay,
here we go,
now with 8 balls.

Let us keep all calculating it with 8 balls,
cause this is the starting position,
where you have the 2.16 to 1 torque start configuration
as I calculated earlier.

ok 8 balls.. so were back to the 2x model? 

the 4x model has  6 balls 10% of the time and 7 balls 90% of the time,
the 3x model only has 8 balls 23% of the time and 7 the other 27%,
the 2x model has 8 balls 97% of the time  (with a 3 degree slope combined with the ramps)

how are you compensating for the -3.6 force on the right side for 10% of the time at 4x the distance?

[zero]

A) I said "Either"   and also, I didnt call him a name.  I simply stated he was lieing
if he was saying there was no additional energy.

Dont twist my words.

And

B)  You dont know what the additional forces would equal out to be,
so dont be so confident.

[hartiberlin]

Okay,
here we go,
now with 8 balls.

Let us keep all calculating it with 8 balls,
cause this is the starting position,
where you have the 2.16 to 1 torque start configuration
as I calculated earlier.

ok 8 balls.. so were back to the 2x model? 

the 4x model has  6 balls 10% of the time and 7 balls 90% of the time,
the 3x model only has 8 balls 23% of the time and 7 the other 27%,
the 2x model has 8 balls 97% of the time  (with a 3 degree slope combined with the ramps)

how are you compensating for the -3.6 force on the right side for 10% of the time at 4x the distance?

I don?t understand your calculation, please show me the error in my
calculation above.
Thanks.

[rMuD]

G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

Then why don?t you calculate  the torque arms ?
Where is my error in my calculation ?

Here it is once again:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units
Devided by 2 cause only for 30 instead of 60 degres
we still have 3.9 versus 3.6.

you error in the calculation is that at 15 degrees on the right side, and 30 degress on the left side

you need 10 balls on the left to have 2 balls on the right to make a closed system

[hartiberlin]

you error in the calculation is that at 15 degrees on the right side, and 30 degress on the left side

you need 10 balls on the left to have 2 balls on the right to make a closed system

?

I just stated, I want to run the system with just 8 balls,
which is clearly enough.
Just calculate it all please based on just 8 balls
inside the whole system inclusive on the ramps,
no more balls in the whole system.