The Lee-Tseung Lead Out Theory

[Koen1]

nice request. Hard to do for "Top Gun"/"Tseung" though,
he clearly doesn't understand physics.

[Top Gun]

Nopes! Absolutely incorrect. Because the moment you are going to introduce your horizontal force from any where above the bob i.e in the string, the whole system is going to change. Weigh of bob, mg, will be always balanced by the straight portion of the string. So the straight part of the string will always have T = mg equation. Because your point of horizontal force application is always going to act as point of support.

The moment you introduce any more new support, they system will look totally different! If you only want to consider three forces i.e. mg, T and horizontal force and if you want to consider this as a homogeneous system with only one point of support, then the force has to be given on the bob and not on string.

Dear Kul_ash,

I believe what you mean by the straight portion of the string = the vertical component of the tension in the string.  I use T1 to represent the tension of the string and hence T1cos(a) = Mg.  In slides 3,4,5 and 6, I no longer use T.

I hope that did not confuse you.

In terms of point of support, in the reproduced diagram pendulum08a, the only point of support is X.   That is the only point of support necessary when bob is in position A and position B.

The horizontal force F is applied via a knot Y shown in the diagram.  Y is not a point of support.  It is a common point where the three forces converge.  This is a simple physics experiment.

Do you agree that such an experiment can be done as shown in figure pendulum8a.jpg?

[ltseung888]

Dear Top Gun,

Thank you for your explanations.  I now have full confidence in letting you explain the Lee-Tseung theory in terms of physics and mathematics.  Please continue to challenge the scientific world and enjoy the juicy discussions.

*** Remember that I shall give a prize money of HKD10,000 (approximately USD1,300) to any one who can disprove the Lee-Tseung Theory.  ***

Meanwhile, I shall work with Ms. Forever Yuen and others to:
(a)   Complete a new presentation file with voice in English, Putonghua and Cantonese.
(b)   Get at least 1 million Students in Hong Kong knowledgeable on the Lee-Tseung Theory.
(c)   Work with the various teams to help to get the low-end Wang Shum Ho Electricity Generator (less than 10KW) on the Market.  The high end has been taken care of by the RMB13 billion Company.
(d)   Consult on the Magneto Propulsion Unit ? engine for the Flying Saucer
(e)   Promote World Peace via ideas from the book in
http://www.energyfromair.com/thebook.htm

Lawrence Tseung

[Kul_ash]

Nopes! Absolutely incorrect. Because the moment you are going to introduce your horizontal force from any where above the bob i.e in the string, the whole system is going to change. Weigh of bob, mg, will be always balanced by the straight portion of the string. So the straight part of the string will always have T = mg equation. Because your point of horizontal force application is always going to act as point of support.

The moment you introduce any more new support, they system will look totally different! If you only want to consider three forces i.e. mg, T and horizontal force and if you want to consider this as a homogeneous system with only one point of support, then the force has to be given on the bob and not on string.

Dear Kul_ash,

I believe what you mean by the straight portion of the string = the vertical component of the tension in the string.  I use T1 to represent the tension of the string and hence T1cos(a) = Mg.  In slides 3,4,5 and 6, I no longer use T.

I hope that did not confuse you.

In terms of point of support, in the reproduced diagram pendulum08a, the only point of support is X.   That is the only point of support necessary when bob is in position A and position B.

The horizontal force F is applied via a knot Y shown in the diagram.  Y is not a point of support.  It is a common point where the three forces converge.  This is a simple physics experiment.

Do you agree that such an experiment can be done as shown in figure pendulum8a.jpg?

No my friend. That is where the problem is!! Simple mechnics tell me any sort of force applied to pendulum may be Horizontal or tangential , is going to "Split" in to horizontal and vertical component in order to move it in radial movement. Vertical component is going to do vertical work of over coming gravity and interia and horizontal component is going to do the horizontal work!! I know gravity is a "restoring" force on pendulum that will always push it downwards and in order to overcome this, I need an "external" force to move it upwards.
I am having too much trouble in understanding how your horizontal force in only doing horizontal work and still giving pendulum a vertical work against gravity, in other words how come its not splitting and still giving a radial motion. The moment you apply the force, a centripetal force is what moves pendulum in radial direction.
So the assumption you have that "EXTERNAL FORCE IS NOT GOING TO SPLIT" is where all  the trouble is! Because you have no theory to prove it. Please show me mathematical proof of external force not splitting to do vertical and horizontal work in a radial motion.
If you keep repeating that, no, my external force is not going to split and it is going to induce lead out energy, the term no body seems to understand, then my friend your and mine mechanics itself is different! Tell me why the external force is not splitting into two components when the motion caused by it is circular.

Mr. Tseung, many people will show you that your above said assumption is incorrect! If you want I can write a complete system in terms of rotational inertia, rotational forces i.e in terms of mechancis. But if you are not ready to accept that your applied horizontal force is splitting, then it means you are challenging the existing mechanics only. You are getting that additional unit of lead out energy because you are considering your applied horizontal force is doing horizontal work only. In my opinion, it is impossible if it is a rotational motion.

[ltseung888]

The difficult problem we shall face if we have abundant energy, technology and capability to travel anywhere.

I shall now tackle this very difficult problem.  Hong Kong is facing such a problem but in a very small scale right now.  The birth rate in Hong Kong is low and the population is aging.  At present, the ratio of 1 retiree (over 65) to the rest of the population is around 6.  In less than 15 years, the ratio will rise to 3.  The medical expenses will rise.  The productivity may drop.  What is the solution to this problem?

Will this problem get worse with abundant energy, wealth and technology progress?

For Hong Kong, the problem is easy to solve.
(1)   The wealth will increase tremendously.  Hong Kong will be credited with the research and development of solution to global warming, solution to the energy crisis and the Flying Saucer.  The confidence of the Citizens will rise.  Visitors and investors will pour in.
(2)   Hong Kong can easily integrate more with China.  The old can choose their retirement homes in China.  The many young Chinese immigrants who want to experience the rapid pace of life in Hong Kong can take up their place.

For China and the World, the problem boils down to ? will the human race drag itself down with a high percentage of old, weak, useless persons?  No politician dares to ask such a question.  His political career will be over the moment he opens his mouth to address such a problem.  This is similar to addressing the sex morality problem in Hong Kong.

It will take someone who do not mind insults and who can think innovatively to work out solutions.  The old, weak, useless retirees are the best to tackle such problems.  This means another challenge for Tseung et al.