The Lee-Tseung Lead Out Theory

[Top Gun]

Dear Kul_ash,

Your questioning of Pendulum14.jpg is intelligent. However, you still commit the mistake of raising too many points/questions in one post.  I shall only answer one point in this reply.

With the string pendulum, it is not possible to provide a perfectly horizontal pull unless the pulling mechanism moves up.  That moving up motion may cause more confusion.

I am drawing Pendulum19.jpg.  It tries to provide a perfect horizontal pull.  It shows a magnetic pendulum in a parallel magnetic field.  This is closer to a constant horizontal force.  The pendulum bob is displaced to the RHS position.  There are three forces acting on it to produce equilibrium.  These are Tension of the string, weight of the bob and the constant, horizontal force F due to the magnetic field.

The NS pole of the magnetic pendulum is aligned in the horizontal direction in this case.  The parallel magnetic field can be produced with appropriate coils or electromagnetics.

[Koen1]

So what you're saying is that you cannot really give an exact
explanation of how exactly this "constant force" can be applied
in reality, to make the system work the way you have been claiming
it works?
Very convincing.

[Pirate88179]

Hey!!  I finally get it!  The pulse, while being constant, is not applied all the time, only intermittently in a constant way thereby allowing no additional energy to be subtracted from the initial constant pulse which imparts a vector force greater than gravity (1g) which accounts for the extra energy lead out of the closed system because gravity is a constant, but the Lee-Tseung pulse is not.  Therefore COP>1.  Of course, since the constant pulse is only applied at the "right" time, conventional mathematics can not be applied to this system due to the uncertainty principle.  By applying math as we know it, you change the dynamics of the system and therefore change the result from that which it would have been if you did not measure it.  Very simple when you think about it...really.

Bill

[chrisC]

Hey!!  I finally get it!  The pulse, while being constant, is not applied all the time, only intermittently in a constant way thereby allowing no additional energy to be subtracted from the initial constant pulse which imparts a vector force greater than gravity (1g) which accounts for the extra energy lead out of the closed system because gravity is a constant, but the Lee-Tseung pulse is not.  Therefore COP>1.  Of course, since the constant pulse is only applied at the "right" time, conventional mathematics can not be applied to this system due to the uncertainty principle.  By applying math as we know it, you change the dynamics of the system and therefore change the result from that which it would have been if you did not measure it.  Very simple when you think about it...really.

Bill

Bill:

It's quite obvious Tseung is so full of crap he's continually contradicting himself; accounting for 'periodic' pulses in order to 'balance' his equations! Someone like this is definitely not a scientist by any stretch of the imagination. Seriously in all my professional life as an engineer I have never seen such low-level life form!

cheers
chrisC

[Top Gun]

Dear Kul_ash.

I shall now address the part of your question related to leverage.

Exactly this is the answer I was looking for. Now refer to your pendulum 14.jpg. It had initial length of M1 which reduced to M2. M1 was inclined so it had vertical and horizontal components. Now when it has become perfectly horizontal means knot is at the same elevation of pulley, no further vertical work is possible. Now you say that mgh = 60 x dH and work done by external force is 10 x dH so where does 50 x dH come from? Now, if you know the simple definition of "leverage" then you should not ask this question. The vertical work done here is through leverage you gave using M1 as length. Have you considered that in your calculation anywhere? Total vertical work done would always be the integration of length of leverage multiplied by supplied force. So it is your leverage that has worked the pendulum up. Whre is the lead out energy?

From http://en.wikipedia.org/wiki/Leverage

Leverage is a factor by which a lever multiplies a force - it is therefore related to mechanical advantage. The useful work done is the energy applied, which is force times distance. Therefore a small force applied over a long distance is the same amount of work as a large force applied over a small distance. The trick is converting the one into the other. The requisite mathematics were developed in the third century B.C. by Archimedes?..

The important word here is ?converting?.  If we want a horizontal force to do vertical work, we need to look for the mechanism that ?converts? this horizontal force to vertical force.  Without this ?converting? mechanism, horizontal force cannot do vertical work.

*** Please ignore the insult training posts from chrisC, Keon etc.  They are noise to distract the serious scientific discussion. ***

I shall pause here for your confirmation.  Do you agree that without a ?converting" mechanism, a horizontal force cannot do vertical work???