PMM by wizkycho

[ooandioo]

Sorry, won't work. Will stuck in the middle position.
Will work if shielding material really "shield" it. I've heard about this material (military applications), but never seen.

You didn't say WHY would it stuck (it is very important to say)?
Like i said this is not "disapearer of flux" (shield) this is mearly PUSH PULL BALANCER but resultant only looks like the part of the field strenght disapeared.

let's not waste to much time on the obvious:
NAKED FACT: Two magnets opposing each other with like poles will get closer if between them stands permeable material and will get further appart if that material is removed !
BTW: military doesn't have it, knowone has it - only god. there is no cancelation of mag. flux only it's rearangement and vector change.

The principle is very clear to understand, i think. The idea itself is also nice but what permeable material will you use. Any metal will also be attracted by the magnets (e.g. MU Metal)...

-- Andi

[wizkycho]

@wizkycho

Thank you for your answer. The two inner magnets (piston) can move freely and easily. So when for example the left magnet gets in repulsion mode, the piston can move easily away and has not to wait until the full repulsion is arrived. Perhaps this makes a small but importent differences.

M.

let rotating side magnets represents input energy Ei
let piston (with its magnets) represent output Eo
let Ef is friction energy loss.
let Eu(usefull) is additional work that piston does when under load

      if piston is NOT under load Ei must be exactly enough to move the mass of the piston + Ef
         therefore your Eo=Ei-Ef => Eo<Ei
      if piston IS under load (pushing some other mass) the input energy must be exactly enough to move Eo(piston) + Eu(add work) + Ef
        in your setup any load or usefull work is transfered directly to input (like in any other no worth mentioning todays motor)
        therefore Ei=Eo+Eu+Ef => Ei is rising lineary with load Eo+Eu<Ei

the only thing that can come to rescue your device (but it is very streched)

http://jnaudin.free.fr/html/2magpup.htm

the tangential force is LESS THAN the axial repulsive force
which would give your device COP factor arround 2

now come to think of it device would WORK  but not the way You explained it

Well done.

[wizkycho]

The principle is very clear to understand, i think. The idea itself is also nice but what permeable material will you use. Any metal will also be attracted by the magnets (e.g. MU Metal)...

-- Andi

permeable means it will attract, it conducts mag flux. both shields ATTRACT => net force at shaft near zero.

steel steel steel. there are many types ones that have high permeabilityes and satturations (for "shieldings") all the way to the ones that are absolutely blind to magnets (not permeable) (like common plastic or common wood) for lever mechanism.
all of these steel types are cheap to get.

Mu metal is expensive and has very low satturation (high permeability though but unusable satturation)
no need to complicate further.

[m668004]

@wizkycho

permeable means it will attract, it conducts mag flux. both shields ATTRACT => net force at shaft near zero.

Yes, both shield attract, but at one shield the endmagnet oft the piston is closer to this shield than the other endmagnet to the other shield, so the net force at the shaft maybe is not zero. I mean, when the lower shield lift up it has to overcome the attraction both of the outer magnet and the endmagnet of the piston. At the same time the upper shield on the other side goes down and is only attracted by the outer magnet but not so much by the pistonmagnet, because its distance is greater then to the other shield. What do you think?

M.

[ooandioo]

@wizkycho

permeable means it will attract, it conducts mag flux. both shields ATTRACT => net force at shaft near zero.

Yes, both shield attract, but at one shield the endmagnet oft the piston is closer to this shield than the other endmagnet to the other shield, so the net force at the shaft maybe is not zero. I mean, when the lower shield lift up it has to overcome the attraction both of the outer magnet and the endmagnet of the piston. At the same time the upper shield on the other side goes down and is only attracted by the outer magnet but not so much by the pistonmagnet, because its distance is greater then to the other shield. What do you think?

M.

Thats what i mean. You will need a non magnetic shield...

-- Andi