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Overunity Machines Forum



WFC Tubes conditioning

Started by Duranza, September 10, 2007, 12:37:03 PM

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0 Members and 2 Guests are viewing this topic.

Duranza

Well I just read the Stanley used Delrin as an insulator. No wonder he always stated you can use any water, even sea water. Having the SS insulated prevents oxidation, but you need to build up a big charge for it to work. This is coming from H2earth's so i trust it's credability. I'll keep at it and i'll just use tap water with the insulated plates until I get results.
The only way to Validate is to Replicate!

Prophmaji

Gentlemen: Please go to the news forum and read the 'white gold' thread in it's entirety, for some hints as to what exactly might be going on here. Don't worry too much if it's a bit strange for you. I know that some of you are going to have the odd 'epiphany' about what you are exactly doing, if you go over there and sift through the stuff I have posted. Read the entire thread. Also read the ER1200 water torch thread. (resonance systems and superconducting ceramic oxides)

While both threads will not spell anything out in perfect clarity..they will provide immense food for thought as to what exactly is going on here with the required oxide layers, and what exactly they may be. I would expect that if one were to make a solution from dead sea salts or the like (with distilled water) and used that create the oxide layer, the results might be more to your liking......an experiment that needs to take place, possibly..after you read both threads.

To add food for thought on top of what I say, go to the ZPE forum..and find the recent (one month old, or so) of the Russian supercapacitor that stores 900 times the energy of regular capacitor, via gold-nanoparticles.

peter from oz

Newby question, lhave my pipes and my circuit box D14 can l condition my pipes with this only. Apologies for ignorance but l'm totally out of my depth with techno speak. l'm producing heaps of small bubbles but no build up of powder. lf l can use my D14 on low output 30min on, dry, another 30m, dry, etc is that it, thanks

Regards

Peter

Duranza

The way I found best is to Pulse them at the lowest frequency that will let you get to 200-300ma. Set the gating for a long off and short on bursts. Change the water as soon as it turns yellow. Don't let it get to brown or your pipes will rust.
The only way to Validate is to Replicate!

Prophmaji

Quote from: Prophmaji on September 12, 2007, 10:02:57 PM
chokes, or inductors, when the one end is OPEN, the coil becomes a CAPACITOR, when the pulse is shorter in length (time wise) than the length of the 'speed of transmission' of the coil. Below that frequency, the coil is 'invisible' to the load. This means, that if you need VERY high speed capacitance, that is FASTER than ANY capacitor, you need a large value coil. What you do, is you place it in the circuit the same way you would put a capacitor, ie, the positive to the hot line and then the other end of the cap to 'ground'. In this case, you do NOT close the circuit. You leave the 'ground' end of the coil OPEN, and the other end connected to where you need the high speed capacitance.

This is specific to buffering high speed DC rails in amplifiers of any sort, or a similar application. There will be a resonance. Exploit it.

I don't care what any given capacitor may be like. This is notably faster, when it comes to delivering pulse current.

The way my old prof taught me to understand this..was clear. He was instrumental in the design and implementation of the original radar [dew line] systems in the upper parts of Canada [alaska, etc] to serve as a early warning system on the old 'cold war' era.

When explaining the reasoning behind proper termination of electrial motor systems in conjunction with switches..the discussion turned to inductive reactance. When a switch is opened, and there is an inductive load in series with this switch..the collapse of the stored energy in the INDUCTOR, not the capacitor.... will eventually, possibly even quickly, cause the switch to fail. He clearly explained that the energy stored in the inductor was actually connected to, on the most basic level..every atom in the universe, in terms of alignment (if we wanted to be technically correct about it!)..and would have to realign, or repolarize itself, with regards to the polarized energy field, or current field surrounding it..from it's charged state...to it's uncharged state. Basically, you have a largely infinite change from DC current field to...nothing.......that must be converted to a voltage field..then back to a current/voltage spike..down the wire of the capcitor. The original current field must go somewhere. and it does. When the inductor has a open end..it has a voltage field that is identical throughout the lenght of the wire. When you have the voltage levels in the  DC rail it is connected to..attemplting to drop in value..it cannot..as suddenly there is a difference in the voltage on one end of the inductor..compared to the other..and suddenly the static voltage field is turned into a extreme high speed dumping current field. But only for the time period that is expressed by the time factors involved inthe speed of propogation down that inductor's wire length.

And..most specifically..when that 'charge state' collapse, for a infinitesimally short period of time..the energy spike was actually INFINITE..but..we could not actually capture and record that infinitely huge and delicate leading edge.

Basically..a temporal disassociation and reconnection effect. Aligned into one state then changed to the next. This follows maxwell's equations in terms of the field considerations.

So..first you have this static charge state of the DC flow and energy field in the inductor. then the DC is 'cut'. the field must collapse. The instantaneous leading edge of the Field collapse..is infinite. For an infinitesimally small time period.

Capacitors have lagging time considerations due to inductive reactance and the fact that the energies must flow through a coiled conductor and coiled pathways. You would instinctively think that a really good capacitor is faster. But no.

in a circuit where you would use a capacitor where the foil lead is connected to the DC rail..and the other lead is connected to ground..a large value inductive coil..with the one inductor's lead connected to the same point on the DC rail as the foil leadÃ,  of the capacitor..and the other lead on the coil is connected to NOTHING...that creates a 'statically charged' high speed coil. When the DC rail attempts to fluctuate in value..the capacitor steps in and dumps energy into the DC line. In the case of the INDUCTOR..which is coupled as stated..the coil will dump the energy it statically holds..at a MUCH FASTER rate thanthe capacitor..as it is a mode of 'inductive collapse' as it tries to maintain a static energy level within itself..it is doing what inductors do..it is RESISTING change in it's charge or 'current field' value.

But, most importantly..it is ONLY doing this as FAST as the energy can travel down the enameled wire, ie, about 80% or so (depends on the given inductor design) of the speed of light or the speed of energy propagation down the wire that describes the length of wire in the inductor. SO..the 'energy dump' (inductive collapse) reaches a 'limit' in 'time it will dump energy into the DC rail' which is exactly equivalent to the length of wire and the speed of propagation in that wire. The longer the wire in the inductor..the longer it acts like a open ended high speed capacitor.

If the inductor is coupled the way it is normally used in a circuit..this effect does not manifest itself as clearly.

This high speed collaping spike can be effectively used to drive the pulse current more effectively in the replication of Myer's work.

That is the entire point for my seeming ramble. My explanation is not technically perfect, but hopefully you guys get the point.