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Overunity Machines Forum



Selfrunning cold electricity circuit from Dr.Stiffler

Started by hartiberlin, October 11, 2007, 05:28:41 PM

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0 Members and 25 Guests are viewing this topic.

k4zep

Quote from: hartiberlin on November 10, 2007, 05:23:22 AM
Hi Ben,
nice to see your picture now with the 30 neon bulbs.

Can you tell us more about this ?  It Used the Ossie On board Osc. 100 ma@ 12VDC in.

Did you also get the core from this Ebay seller
Mr. Lowe from Middletown, OH 45044 ?  I got from zlowe7 in Cincinatti, Ohio.  Possibly the same guy.  Coils seem the same.

Do you now see much more amplification with it ?  It shows all the needed charactoristics.

How much power did you put in there to drive
the 30 neon bulbs and at what frequency ? 1.1 watt @ 9 Mhhz

What is you voltage p-p to drive this from your signal generator ?  Osc on board, battery powered.

Can you , if you hit the resonance frequency of the core
lower in the input signal generator  voltage , without the neon bulbs
reducing their brightness ?   Brute force, no resonance, did not try to resonate.

Have gone so much further since this "teaser", MOST important, you must operate this system open loop during power generation for the OU effect to be there.  The Ossie C. circuit is just a start, works good.  Always better ways.  It is amazing, there is these "globs" of power generated at the end of multiple AV plugs/loops.  To use it is the basic problem.  Closing the loop is the hardest to do, or transfering OU energy back to normal operating system.......
If yes, to what level ?
Many thanks.


DrStiffler

Quote from: hartiberlin on November 11, 2007, 03:16:35 AM
Quote from: derricka on November 10, 2007, 09:03:21 PM
Hi Harti
The reason the voltage drops on the test circuit at self resonance is that the measurement circuit  is in SERIES with the coil. 

Yes,but in the circuit diagram he is showing it being measured across the 50 ohm load resistor.

If the series LC circuit atresonance has about less than 1 Ohm impedance, all
voltage should be at the 50 Ohm resistor, so the voltage should
be maximum at resonance, not lowest... or do I mix something up here ?

The measurement procedure is correct and the results are correct. Many have already explained why this is so, but I will attempt to do so also.

The coil (turns of the coil) between each turn, has an intrinsic capacity that forms a mini-parallel resonant tank, so picture the coil and its inter winding capacities as a string small parallel resonant tanks in series. A parallel tank will exhibit highest impedance at resonance, therefore lowest voltage across the 50-ohm resistor.
All things are possible but some are impractical.

Joh70

I realy do not understand, why there is nobody, who closes the loop to plug off the battery or an external powered signal generator!!! To close the loop, use a mini-solar-panel, fed by the light of the LEDs. To start-up the circuit, put external light on the panel, powered by a battery/supply or so. After successfull initialization switch off the battery and remove it completely. WHAT YOU ARE WAITING FOR???

DrStiffler

Quote from: Joh70 on November 11, 2007, 01:18:47 PM
I realy do not understand, why there is nobody, who closes the loop to plug off the battery or an external powered signal generator!!! To close the loop, use a mini-solar-panel, fed by the light of the LEDs. To start-up the circuit, put external light on the panel, powered by a battery/supply or so. After successfull initialization switch off the battery and remove it completely. WHAT YOU ARE WAITING FOR???

Maybe the Wine needs to age a bit more and hey its not Christmas yet.

Hang around, something better may be blowing in the wind....
All things are possible but some are impractical.

amigo

Isn't closing the loop going to break the dia-pole and rid us of the radiant energy being created? When that happens we end up in the realm of the underunity where all of our conventional devices work in...but not really where we want to be.