Selfrunning cold electricity circuit from Dr.Stiffler

[MeggerMan]

Hi Stefan,

is this a typo and you wanted to say:
"that the cores..."

It is correct to say "in that the coils", this makes perfect sense to me.

Perhaps another way of writing this sentence would be:

"It now appears that I have been partially in error, the coils themselves do not create the OU effect but they can enhance it."

I have been winding some air cores this evening for people without LCR meters to be able to wind their own.
2.2uH can be achieved by winding 12 turns onto a 15mm former using 0.56mm enamel copper wire.
I used a highlighter pen as the former, wound the turns then locked them in place using PVC insulation tape.
Then I was able to slide the coil off the former.
I need to order some lintz wire to see if I can get a better Q, currently its only 0.19 at 1KHz.
Although I have a lintz air core wound on waxed paper former that measures 2uH and its Q at 1KHz is very low, like 0.002.
I also had a core with 11 turnsÃ,  wound on a 15mm former and the Q was slightly lower at 0.15 but this has more tape on it.
I am wondering if I glue it with epoxy to make it rigid if the Q would be better.
Maybe smaller diameter coil, thinner wire, or even a torroidal air core.



Regards
Rob

[hartiberlin]

Okay, my new video is now online:

http://www.youtube.com/watch?v=qRw_sCzhFnk


I just checked again the input power:

12 Volt and 3 mA when I disconnect the coil ,Avramenko plug and LEDs from the output.

12 Volt and 7 mA when I have the LEDs running

So 84 mWatts with LEDs - 36 mWatts without LEDs= 48 mWatts power for the running LEDs,
so do I have more brightness then 48 mWatts ?
Have to check this out with more LEDs.

[hoptoad]

So 84 mWatts with LEDs - 36 mWatts without LEDs= 48 mWatts power for the running LEDs,
so do I have more brightness then 48 mWatts ?
Have to check this out with more LEDs.

Stefan, if you supply 12 Volts DC into a LED via a 1 k-ohm resistor it will consume roughly 12 milli-Amps of current. Therefore its power usage will be 12 V x .012A = 144 MilliWatts. This one "standard candle" already uses slightly more power than your total circuit consumption.

Why not use this "standard candle" to compare the luminescence of each LED to it for a reference point. You could set up a little ohm-meter connnected to a LDR which is set inside a small black plastic tube which could then be placed over each LED for measuring the "relative" light output. It would be more accurate than the human eye in detecting real Lumin levels and trying to determine relative brightness.

I noticed when looking at your video, that you had about 8 or 9 LEDS glowing very brightly!   
If each one was glowing at least as brightly as a "standard candle", then your Lumin output would be well over the expected output for the megre 84 milliwatts total consumption that you're circuit is using. Even if each LED was only half as bright as a "standard candle", the total number of LEDS may still be exhibiting a greater total brightness than 84 milli-watts might normally produce from standard DC.

Measuring input may be easy but measuring output seems to be the hard thing!

Some sort of reliable standardised output comparison method needs to be implemented to give an empirical framework for your
results.

Great research, great video. Great stuff Stefan!

Cheers from the Toad who Hops 

[xee]

Tests on LED apparent brightness:
The human eye detects peak light levels. There are cells in the eye that trigger when light above a specific level hits them. These cells send a message to the brain saying that there is a light in a certain location. It takes time for these cells to reset. If after some time has past and they have reset and they are again triggered and send another signal to the brain, the brain assumes that the light was on continuously the full time between signals. When pulses are used to power a filament light bulb, it takes time for the bulb to turn on and the bulb will look dim if only short pulses are used. But LEDs turn on very quickly and so will reach full brightness even with very short pulses. I used the following circuit to determine how little average power was needed to make an LED appear to be at full brightness when it is being pulsed. This circuit develops several hundred volts at the collector and produces very short pulses with high current. Thus the LED is turned on very brightly for only a small part of each cycle (about 1%). It is very difficult to measure current pulses accurately. This circuit accomplishes this by measuring the current through the resistors after the capacitor at the LED output has fully charged. At this time no net current is going into the capacitor and it has a relatively steady voltage across it making it possible to make an accurate measurement of the voltage across one of the resistors (from which the current can be calculated). The LED used for this test was a super bright green LED rated at 15,000 mcd at 3.6 volts and 50 ma. which would be 180 mw power consumption for full brightness. But as the test shows, the same apparent brightness was obtained using pulses with only 0.43 ma average power which is only 1.5 mw. Therefore the LED was actually consuming about 1% of the power requited for the equivalent brightness using continuous current instead of pulses.

[hoptoad]

Tests on LED apparent brightness:
The human eye detects peak light levels. There are cells in the eye that trigger when light above a specific level hits them. These cells send a message to the brain saying that there is a light in a certain location. It takes time for these cells to reset. If after some time has past and they have reset and they are again triggered and send another signal to the brain, the brain assumes that the light was on continuously the full time between signals. When pulses are used to power a filament light bulb, it takes time for the bulb to turn on and the bulb will look dim if only short pulses are used. But LEDs turn on very quickly and so will reach full brightness even with very short pulses. I used the following circuit to determine how little average power was needed to make an LED appear to be at full brightness when it is being pulsed. This circuit develops several hundred volts at the collector and produces very short pulses with high current. Thus the LED is turned on very brightly for only a small part of each cycle (about 1%). It is very difficult to measure current pulses accurately. This circuit accomplishes this by measuring the current through the resistors after the capacitor at the LED output has fully charged. At this time no net current is going into the capacitor and it has a relatively steady voltage across it making it possible to make an accurate measurement of the voltage across one of the resistors (from which the current can be calculated). The LED used for this test was a super bright green LED rated at 15,000 mcd at 3.6 volts and 50 ma. which would be 180 mw power consumption for full brightness. But as the test shows, the same apparent brightness was obtained using pulses with only 0.43 ma average power which is only 1.5 mw. Therefore the LED was actually consuming about 1% of the power requited for the equivalent brightness using continuous current instead of pulses.

Fantastic observation XEE.
It is my contention in these sorts of experiments, that "apparent" outputs can be just as useful as "real" outputs.
When designing lighting for example, the information you just furnished can result in great savings.

If the human eye only needs a very bright light for a very brief time, to "perceive" that it's a very bright light all of the time, then O/U is not necessary to make major breakthroughs in energy saving lighting methods. If the human eye perceives that the light is bright, then the light has done it's job!.... KneeDeep.....

Thanks for publishing the circuit and chiming in with your info. Well timed!

Cheers from the Toad who Hops