Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Selfrunning cold electricity circuit from Dr.Stiffler

Started by hartiberlin, October 11, 2007, 05:28:41 PM

Previous topic - Next topic

0 Members and 22 Guests are viewing this topic.

armagdn03

@fritz

so you are saying that we have an impedance matching issue? if thats the case here is one to consider,

does the impedance of the plug affect the driving circuit? (excluding the generator)
I wish I could turn my brain off sometimes, then I could get some sleep.

Mr.Entropy


Quote from: armagdn03 on October 23, 2007, 12:57:43 PM
If we are basing the results off of the barium ferrite core resonanting at a frequency of 10Mhz, then why is it a linear growth on the graph, with no decernable change in characteristics floating around the 10Mhz resonant point?

It's because there's nothing in the core that resonates around 10MHz.   That 10MHz figure you have is for nuclear magentic resonance imaging.  At the atomic level, that means:

- You apply an enormous magnetic field.

- Like a clock spring attached to a flywheel, the magnetic field keeps the atoms aligned in a particular direction.

- If you disturb the alignment, they'll oscillate back and forth at some frequency, again like the flywheel+spring.

- If disturb them with an oscillating force at that frequency, they'll resonate and their oscillations will grow (relatively) large.

Now, in exactly the same way that the resonant frequency of a wheel+spring depends on the strength of the spring, the resonant frequency of an atom in NMR depends on the strength of the magnetic field.

That is why the figures were quoted relative to H at 100MHz.  It means that if you apply a magnetic field of the strength that makes H resonate at 100MHz, then barium will resonate at 10MHz.

If you don't apply an enormous magnetic field at all, you don't have any of this kind of nuclear resonance at all.

Cheers,

Mr. Entropy

edork

Hi fritz!

Hey nice but where you built Stifler circuit? So what you mix good fruit with bad?

fritz

Quote from: Mr.Entropy on October 23, 2007, 03:06:13 PM

Quote from: armagdn03 on October 23, 2007, 12:57:43 PM
If we are basing the results off of the barium ferrite core resonanting at a frequency of 10Mhz, then why is it a linear growth on the graph, with no decernable change in characteristics floating around the 10Mhz resonant point?

It's because there's nothing in the core that resonates around 10MHz.   That 10MHz figure you have is for nuclear magentic resonance imaging.  At the atomic level, that means:

- You apply an enormous magnetic field.

- Like a clock spring attached to a flywheel, the magnetic field keeps the atoms aligned in a particular direction.

- If you disturb the alignment, they'll oscillate back and forth at some frequency, again like the flywheel+spring.

- If disturb them with an oscillating force at that frequency, they'll resonate and their oscillations will grow (relatively) large.

Now, in exactly the same way that the resonant frequency of a wheel+spring depends on the strength of the spring, the resonant frequency of an atom in NMR depends on the strength of the magnetic field.

That is why the figures were quoted relative to H at 100MHz.  It means that if you apply a magnetic field of the strength that makes H resonate at 100MHz, then barium will resonate at 10MHz.

If you don't apply an enormous magnetic field at all, you don't have any of this kind of nuclear resonance at all.

Cheers,

Mr. Entropy



The self resonant frequency of an AM ferrite antenna is around 10MHz.
This resonance is given by the inductivity of the coil and the parasitary
capacity of the winding. Every winding builds somewhat capacity to the
next winding. This distributed capacity forms a parallel LC circuit - in this
case with resonance around 10MHz.
The primary coil on top of the original coil forms another parasitary capacitor -
in our case around 20-40pF

rgds.

fritz

Quote from: armagdn03 on October 23, 2007, 03:05:18 PM
@fritz

so you are saying that we have an impedance matching issue? if thats the case here is one to consider,

does the impedance of the plug affect the driving circuit? (excluding the generator)
Even if you see no ground here on the schematic of part2, there is straight
ac/rf path from the led to the generator. Any change in this path - including
a measurement with the scope or a change in the connection to the generator
changes the load from the perspective of the generator. This is why a replacement
of the led against a big capacitor changes the current from the generator, the voltage
on series resistor R2.
rgds.