Muller Dynamo

[plengo]

Attention: the site below provided to calculate your capacitor for a certain inductance and frequency has a trojan virus. By simply visiting the site it will contaminate your computer and allow others to access your machine.

Hi Laurent,

I would suggest doing also Penno's capacitor placement in parallel with the two series drive coils. Use the tacho meter to know rotor RPM then calculate rotor frequency (say you have RPM=1800, divide it by 60 to get frequency in Hertz (1800/60=30 Hz). Now measure the inductance of two series drive coils with your L meter (consider measuring when rotor magnets are furthest away and when just sandwiched by the coils and take the average of the two L values).
Then you can use the Thomson formula to get a ballpark figure for the capacitor value (non electrolytic). You may wish to use this link for the formula: http:// www (dot) whatcircuits.com/lc-resonance-frequency-calculator/

If you say find an average L=2.5 mH for two series drive coils and use the 30 Hz frequency the link above gives 11258 uF, a very high value because L  and the frequency is very low.  I know it is difficult to obtain (and expensive) such high non-electrolytic caps, so the closer you approach the better... Or just try any microFarad you happen to have (4.7 or 10uF) and watch how input current tends to go down. As an alternative, you can use this:

  Connect two electrolytic capacitors of twice the uF rating and at least equal voltage rating back-back in series. To minimize any significant reverse voltage on the capacitors, add a pair of diodes:
           
                    1N4001 to 4007 diodes
               +---|>|---- + ----|<|----+
               |                |                 |
               |   -     +     |     +    -     |
         o---+----)|------+-----|(----+------o
                 2,000 uF     2,000 uF
                   25 V         25 V

This way you can get a non-polar capacitor with 1000 uF value, rated to 25V, just try this putting in parallel with the two series drive coils and watch input current.  I know the calculation gave 11000 uF but no need yet to rush for two 22000uF and connect them in series if you do not happen to have them now.

Gyula

[Arthurs]

@woopy,

Untill I get the video camera -

1.  20v @ 200ma  + 6.8uf ac cap = 1800rpm

2.  20v @ 400ma no cap = 1630rpm

Hi penno64

6.8uf cap specific in what position? A schematic description of it?

Thank you!

[gauschor]

@plengo: I cannot confirm this. This warning made me visit the site but Antivirus found nothing. Can it be that you got your Trojan Horse from somewhere else?

[AbbaRue]

2 Things that differentiate this motor/dynamo from most I have seen is.
1) The magnets are spinning instead of the coils. 
2) It has magnets placed on top of the coils to balance the magnetic fields.   

I believe the balancing magnets are the key to the OU. 
The washers serve as a way to keep the magnets in place so you can quickly place and remove them for adjustments. 
Also the washers spread the magnetic field out across a larger surface. 
So I believe our main focus in getting OU from our dynamo's is in adjusting those magnets placed on the washers. 
As well as getting the right size of washers, and right strength magnets for them. 
Another focus would be in getting the distance between the coils and the rotor at the right distance.
I believe that by getting those things right, every ones replication will reach OU. 

I'm in the process of acquiring the parts to build my own. 
I still need the large rotor disk cut accurately and I'm waiting on the litz wire to arrive. 

[baroutologos]

@ Above,

I silently watch and do not want to theorize at all. After all , the theories little contribute at all.

So, when Romero was discussing his generator with all S magnets facing up (changed from an initial NSNSN magnet polarity) and after a lot adjustments he said he achieved OU without the "regauging" or "compensating" magnets at all. But OU percentage, according his calculations was about 1:1,1 or so.

The back end magnets almost doubled the output affecting the input only a bit. So looping afterwards was a piece of cake according him.

see for yourselves https://rapidshare.com/files/4084301451/Forum_page_8.zip