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Overunity Machines Forum



Power ratio over one

Started by handyguy1, January 03, 2008, 09:33:54 AM

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0 Members and 3 Guests are viewing this topic.

gyulasun

Quote from: handyguy1 on January 28, 2008, 10:52:29 AM
Hay Gyula:
I am not doing a good job of explaining what is happening, sorry.

When a load is increased, resistance should increase. The device should slow down. If I put a couple of mini lamps (or more) in series with the LEDs, they don?t light up, and the LEDs show no difference in intensity, and there is no slow down of the device. If I put one or more 10-ohm resistors in series there is no difference in the LEDs or the devices speed. I have even used three small 1.5-3 volt motors in series, and there is no slowdown in the device and the LEDs continue to blink away!
I would at least expect one-half cycle to show signs of resistance and slow down, but it doesn?t.
I could understand that the LEDs used up the amperage, when the power was going through the LEDs first, meaning that anything else in the circuit would be just a return path to complete the circuit. However, I can?t explain when the power goes through the resistive load first, why that doesn?t make any difference. Does this explain my dilemma any better?

David


Hi David,

I decided to draw a rough schematics how I think you may have connected your LEDs as the load, ok?  Because without a diagram it is difficult to speak about the happenings and know if we think of the same setup.
In Fig. 1 I indicated the positive half wave voltage only, and the current in red too.  One and the same current flows through the resistor and the LED line with the forward direction to this positive voltage, ok?
In Fig. 2 I indicated the negative half wave voltage only, and the current in blue, too.  This current must be of the same amplitude in theory than that in the positive period but if the up/down distances differ  a little in the see-saw or the LEDs are a bit different, then the time (and the amplitude) may also differ a little.

So the answer to your dilemma is, that it is all the same which component the current goes through first, a resistor or a LED line, it does not matter.  What counts with respect to how big current is able to flow is that how bigger the induced voltage than the summed LEDs forwards voltages.  The bigger the induced voltage, the bigger the current, but the treshold voltage from which this counts is the summed up LEDs forward voltages, always, whenever you use LEDs as loads. And the difference is 5-10Volts I guess and NOT the full 40-60V coil output!
And if you use series 10 or 100 Ohms as an addition to the LEDs load, then the voltage drop is able to appear across them only at times whenever the induced voltage is higher than the LEDs treshold voltage (because under the treshold voltage there cannot flow any current in the diagram I show) and because it is not the full coil voltage which drives the current through it but only the difference, hence this current can drop a smaller drop across those low value resistors. And the result is you do not sense this indeed small effect.

If you happen to use a different schematics at your output as a load, please describe it or better, draw it.

rgds
Gyula

handyguy1

Hay Stefan:

I posted a new video on you tube. I hope it shows what you are looking for. I am looking at Guyla's schematic and will try to make one up for you.



Hay Gyula: I need a little time to digest your schematics!

gyulasun

Quote from: hartiberlin on January 28, 2008, 05:35:03 PM
Hi David,
please show the driver unit in detail with macro photos.
How do the electromagnets lift up and down the wood ramp
and the axis ?
Is there anywhere a magnet involved to do this ?
Many thanks.
Looking for a new video from you that clears this up.
Many thanks.

Hi Stefan,

So the electromagnet is his first copper color coil (just next to left of the green color coils) in the middle of which the long shaft with all the magnets also going through and is able to make the see-saw movements and this copper color (air core) coil is controlled by the four microswitches. And the microswitches are controlled by the see-saw movement of the arm #4 fixed to the left end of the long shaft and this arm is placed mechanically above  another see-saw arm (#14) that actually operates the 4 micro switches.  No extra magnets near or around the switches are used.

Gyula

handyguy1

Hay Gyula:
Your schematics are accurate. I just posted a waveform at ou_builders. I overlapped the input and output waves.
Notice how on the top line (input) as the voltage goes up the amps go down. Amps don?t follow the voltage.

David

Your discription of the switch operation is also correct!

gyulasun

Hi David,

When you find some time and you happen to have a digital multimeter (an analog meter also will do of course) with resistance measurement range, would you check the DC resistance of your input (copper color) and output green color) coils?  I am curious...  :D   In my schematics I indicated a 50 Ohm resistance in series with the LEDs, its value is symbolic of course, and can include one of the green coils resistance of course.

Also, would you tell us what loads did you use for getting those waveforms you just uploaded at ou_builders?

Thanks.  Please take your time, no need for a hurry.

Gyula