Thane Heins Perepiteia.

[Steven Dufresne]

Larry, that was one of my questions also plus the permeability numbers. I will be talking to Thane tonight!...our time is E.S.T.

Luc

Luc,
And if I'm not too late too, can you ask what frequency, roughly is okay, he uses?
-Steve
http://rimstar.org
PS. Almost all aluminium/lead grinded off the core. Had to come inside in case an local couples were having a romantic dinner. The sound of my grinder would probably hurt the mood. 

[gyulasun]

Hi Steve

Here is the diagram of my transformer.

Vince

Hi Vince,

Thanks for your info.  Would like to help you in getting to know whether how much current is able to flow in your output coil in the main core when you load it with something or short circuit it. 

I assume you may have already tried to load it with something like a light bulb or a resistor? 

If you short circuit your output coil, then the current is determined by the copper coil resistance of the output winding.  So when the primary is completely disconnected from the mains, you can measure the DC resistance of your output coil with your multimeter set to the appropiate OHM range: if that winding served originally as a mains transformer primary, then its DC resistance can range from some 10 Ohm to some 100 Ohm.  When you know this DC resistance, you can divide the 62V with that Ohm value to get the short circuit current value. 

Now if you find your output coil DC resistance is  -say-  332 Ohm,  then the 62V unloaded output voltage will create a current of 62/332=0.1867 Amper in the output coil when you short it and when the primary is switched onto the 120V mains. 

Because NOW you know what current to expect in a short circuit case for your output coil, you could connect a certain value of resistor in series with your current meter. Say you have a 22 Ohm resistor at hand, then the expected current will be 62V/(332+22Ohm)= 0.175 Amper, this is the current value your meter should show with a some percent accuracy. (The resistor wattage need is not high: 0.175*0.175*22=0.673 Watt so a 1W rated 22 Ohm resistor will do for a short time current load measurement.)

In case you happen to have a clamp-on current meter, then you directly connect the load resistor to the output coil and clamp on the wire to see the current.

The method I outlined corresponds to a normal mains transformer load test but your transformer is not a normal one because you have found no input current change at your primary input (the current remained at 1.2 Amper) when you shorted the output coil so I look forward to your measurements     (by the way, the 1.2A is rather high input current for an unloaded transformator,  I suspect core saturation,  what if you used the so far secondary output coil as the input primary coil and the other coil as the output coil,  so actually you reverse the role of the coils?  a normal unloaded conventional transformer consumes about 50-100mA of primary current from the mains) 

rgds,  Gyula

[gyulasun]

Hi Gyula,
Mr. Frolov did mix this up.
It was not me, who has built this Phi machine generator,
but Steven Sullivan from Omnidyne corporation.

OK Stefan,  thanks for your answer.

Gyula

[gotoluc]

Hi all,

I received an email from Thane but only now noticed it had attachments of information that seem to be about the split phase induction motor and permanent magnet test. I attached them below and also the message (red) Thane wrote in the email.

I did not post the NASA letter of invitation to Thane that he is referring too, since it may not help in the testing or replication. But if anyone would like to see them please ask and I will post it.

Luc

Dear Luc,

This information may also be of use to your group.
People need to understand that the generator coils voltage and CURRENT are increasing with increased system speed.
You also should notify them about my invitation to present at NASA.
Cheers
Thane

[johnnyl]

I am interested in seeing the NASA letter.  Thanks... J