Pulse motor - is this overunity?

[tinu]

The measured voltage ... at output is it 11,6 V.

Then I have:
...
At R2: 0,0523 A * 11,6 V = 0,6067 Watt

Either current but most probably the voltage (11.6V) can not be correct because:

on R2: 0,0523 A * 0.1 Ohm = 5.2mV
and
on R3: 0,0523 A * 33 Ohm = 1.7259V

so, on R2 and R3, if current is properly measured, you should have 1.7311V, which is in contradiction with 11.6V.

One question though: what is ?output? actually? R2 or R3? Normally is R3 of course, but from your post (power calculus on R2) it seems that you consider R2 as output.

Cheers,
Tinu

[Groundloop]

@mr2,

Remove the R2 and measure the voltage over R3. Then you can calculate the output.
Measure the voltage over R1 and calculate the input current. Then measure the voltage
over the input of your circuit. (Inside of R1, direct on the input.)
Then you can calculate the input power.

Groundloop.