Roll on the 20th June

[OU-812]

@OU-812

There are weights on the ends of the rod that weigh more than the water that is 'moving' down to the left. Remember you can lift a lot of weight via buoyancy.

Ok, point taken, how about speed of the transfer?  If the wheel is turning could you get enough buoyancy to get it where it needs to be fast enough?

Edit:  I re-read your original post.  Do you mean to say it wants to float back up (to the upper left) when it gets past 3 PM (rather than 2PM) and you are looking for a way to 'fix' it in place until after 6 PM?

[hansvonlieven]

show me a drawing, I cannot make sense out of this. If water does not move you cannot have buoyancy.

Hans

[House]

@OU-812

Good question, haven't gotten that far yet. Need to figure out how to get it to spin around to 6pm first...since the rod wants to move back up and to the left when it reaches 2pm, trying to figure out a way to lock the rod into place when it shifts from 7 to 1 and then release it at 6pm...or earlier depending on how long it takes to shift. Remember the rod is most of the length of the tube...so it only needs to shift a short distance a la Archer's first description of his shifting rod wheel.

[House]

---delete---double post. 

[House]

@Hans

Take a tube and fill it completely with water. Then stick anything with positive buoyancy inside the top of the tube...the tube will overflow as the water is displaced by the object. Then turn the closed tube upside down. Then object will float back to the top of the tube. That is what the rod is doing.