Roll on the 20th June

[0ne]

Also, Archer, I wanted to tell you don't give up total hope on Newton. Actually his work will come in handy when you learn more about magnetism.

He knew a lot more about this universe then he told. I'm sure that is because of his work with the Emerald Tablets.

[ramset]

Helmut  sounds very good LOTS of power   MY head is spinning can't sit still    Grandma's not going to freeze this winter elec heat      Chet

[xbww]

I am a complete newbie at PM (but learning quickly  . I am a computer programmer so I am not stupid. But, why not engineer a lever at 7:00 that the rotation/momentum of the wheel trips to shift the bar up rather than using the magnets? Or, why not use a small servo motor to mechanically lift the bar? If the wheel can generate enough electricity to run your house, can it not trip a lever or provide power to a tiny servo that would lift the bar? That way you could forget the magnets and simplify the design.  I asked earlier "how much power" does an electromagnet require and an answer came back that it was way more than the wheel could produce. At least that is what I understood.

My mind goes from "this won't work" to "maybe it will". To be honest, at this point, even though we know the "secrets", until one is working, we'll never know. 

I am confused?   

PS. Anybody know were to get an electromagnet that would be appropriate for a protoype?

[sm0ky2]

momentum of the wheel is 1/2m*(V^2)

i personally dont have the time / patience to sit here and calculate the torque conversion of the mass of the wheel vs the gravitational acceleration of the weight-mass on its outer perimeter, for every point around a revolution.
which is why i am using the instantaneous kenetic energy value if you were to "stop" the wheel at 6-o'clock
from the weight falling from 12:01

theoretically, they should total out the same on a 1/2 revolution, but  because the wheel incurs a negative acceleration on the "up"side, the total energy value of 1 complete revolution = 0, with the weight ending up back on top having the same kenetic energy you put into it when you placed it there at he begining of the cycle.

We have to, therefore, make use of the momentum of the moving mass (at 6 o clock) - and use a portion of this energy to lift the much smaller weight back to the top. thereby circumventing the circle - as archer puts it.

[sm0ky2]

@xbww

do you have any ideas as to how to engineer this lever.

i would want it to take a horizontal force at approx.:  6:01
and convert it to a verticle force moving the weight from 6:01 to 12:01.
(6 & 12 is for maximum efficiency, you could use 8 and 2 and it may still be applicable)