new? magnet/gravity motor

[2b]

> you've sold me on the idea ...

YES!  I CAN SEE THAT YOU UNDERSTAND!!!

i tried to describe all the forces involved, but it started to take several hours!!!  there's a lot going on for such a simple device.  gravitational, centrifical, weight/momentum, magnetic - lots of forces.  but it is much easier if you can see it in your head.

things of note, which you have seen:

1. the lower-left static magnet should be more powerful than the upper-right static magnet.  as the lower cylindrical magnet passes the lower-left static magnet, the "bump" of the repelling forces to the upper-right actually works on both cylindrical magnets, since the cylindrical magnets oppose each other on the spoke.  the "bump" also works against gravity in moving the lower-left cylindrical magnet against gravity in rotation, and against the magnetic attraction at the upper-right as the cylindrical magnet leaves the static magnet.

2. stainless steel shielding, especially to the right of the lower-left static magnet, will actually ATTRACT the oncoming cylindrical magnet, whereas, normally it would be repelled, opposing CW revolution.

3. the "bump" that shifts the cylindrical magnets on the spoke should shift them at least half-way up the spoke (toward the upper-right).

4. it would be good to have the spoke well greased, and made of wood or something so as to not interfere with the magnetic fields.

it's tricky, but no matter how i look at it, i keep seeing that the forces favoring CW revolution can be made to outweight the forces opposing CW revolution.  it is almost like a vertical axis wind-turbine - except you have gravity working on one side, and magnetic forces (anti-gravity) working on the other side.

[2b]

> Hi all ive thought simler to this and im glad some of you are trying it cos i dont really have the tools or things to do so, i dont want to be negative but on the right side when the magnet is being pulled up it will get stuck in attraction mode to the external magnet , the magnet would then have to weigh so much to break itself free of the attraction and if it does so weigh that much then it would not lift up in the first place.

you are not taking into account the CW momentum - the cylindrical magnets don't have to get shifted more than 1/2 up the spoke in the upper-right direction, at which time, their momentum carries them on in a CW direction.  it is probably something that will only work at a certain steady-state RPM.

> You mention using sheilding thats a good idea on the left side tho i think if most the thrust makes the magnet go inwards it will be less upwards

yes, there is a balance to be achieved.  there are many factors - the shielding, the magnet positioning, sizes/strengths of the magnets, the speed of the spoke and related forces, etc.  it is only important that the cylindrical magnets get shifted passed the half-way point on the spoke.

> and on the right side when the magnet goes into attraction mode what sheilding material would you use?

at the upper-right, you would only have worry about shielding as the cylindrical magnet leaves the static magnet - but this is less important than the shielding on the lower-left static magnet.

the lower-left static magnet has much more work to do than the upper-right static magnet.

> sheilding to my knowledge is usally tin or some other metallic meterial and is mainly to use on like poles cos with like poles the magnets have repulsion + attraction from the tin etc so you get a neutral effect but with opposite poles the magnets have attraction + attraction so you will only get attraction, if there are non metallic meterials used for sheilding what are they?

stainless steel plates used as shielding act as stainless steel - they negate the effect of poles and make similar poles "attract" - because both similar poles are just attracted to the steel.  shielding has to be a magnetic material to trap the field.  i can see the person with the diagram understands these things very well.

[2b]

> i havent given much thought yet to the "sliding mechanism" of the rotor magnets, if that proves to be necessary.

i think i would just use those cylinder wood sticks they sell at hardware stores - sand them and grease them and put a nail thru the center.  they are like long chop-sticks.

[2b]

> this tupe of dewices never could work because there are no energy input .

it isn't a matter of "energy", it is a matter of work, Force x Distance, and there are a lot of things doing work here.  energy is either potential or kinetic - it is the outcome, not the predecessor.

you have gravity doing work on the right side, and magnetic repulsion (anti-gravity) doing work on the left side.  the trick is to not allow any work to overpower the work of those forces.

> if one piece of something drop down you need energy to put it up agen.

yes, the lower-left static magnet - it is "anti-gravity".

> you need to breake gravitu if you want get weight back with les energy used.  you lose energy not only to move up and down weight but to move horizontaly too.

no - you gain energy due to the work of the lower-left static magnet, which serves to do the major work of shifting the cylindrical magnets, as well as doing some anti-gravity work to boost the cylindrical magnet on the left side up ...

> thus is why this grawity pendelum systems not work. and similar is problem with magnetic permamanet motors you need energy tu put something in magnetic field.

yes, the work done by gravity on the right side, along with the attraction of the shielding on the lower-left static magnet, serve to get the lower cylindrical magnet into the magnetic field of the lower-left static magnet.

[2b]

> I have build this exact device and it didnt work. The repulsion of the lower magnet is bigger then the gain of the shifting weights.

it doesn't sound like you used shielding.

> Another thing is that if your give it a good spin, the centrifugal forces stop the magnets from shifting, the just stay on the outside.

that is a factor - it depends on the RPM and the weights and the magnetic attractions, etc.  i would say that this device will only work at a certain RPM, but it will strive to maintain that RPM even after a load is attached.