David Bowling's Continuous Charging Device

[markdansie]

I admire your efforts and keep up the good work.
You have an interesting project. It is not producing overunity or excess energy, but you are fixing up some old batteries.
The results you are seeing are attributed to many things under the tittle "Battery Effect"
These include surface charge, desulfating, and changing the architecture of the plate surface. All are very explainable.


Now run it with a bank of caps continuous and you will have everyone's attention.
Kind Regards

[profitis]

@markdansie..we dont know that for sure.we have back-emf spikes evry time the brush passes a gap,whers the energy of the backspikes going into?@bowling,the thought occured to me that the dead bat is acting as some sort of diode either allowing use of the backspike or itself being charged by the backspike.current will go easier in one direction through a bat than the other,even if dead,im just toying with ideas here..

[Dbowling]

We have three people in different parts of the country with working devices. All you have is your opinion. Either build it and see what it can do, or go away. I have no time for you. I am doing hours of test runs every day without ever charging the primaries. But just to annoy folks like you even more, I am going to the store tomorrow and buy two of the smallest amp hour 12 volt batteries I can find. My load doesn't change. It is a 12 volt motor that pulls 11 amps running another motor as generator. When I put a load on the generator it draws even MORE amps, but we won't go into that. The amp draw was taken with both an analogue gauge shown and a digital meter. It has been checked more than once and is ALWAYS at least 11 amps. Here is the video.


http://www.youtube.com/watch?v=xw5O5Cn7Nug[/font][/size]



Now, if I am not lying about that, how long would you expect I could run that load even if the voltage in all five of the batteries we are using in the system were full. We have three 18.5 amp hour batteries, one of which we drain down to 12 volts or less before putting it into the system. And we have two 4.5 amp hour DEAD batteries we are using as our transducer batteries which show less than 2 volts. So even if all of these were full, how many amp hours of run time could I expect to get out of my motor?
3x 18.5 = 55.5
2x 4.5 = 9
-----------------


65.5 amp hours


divided by 11 amps. is a little over five hours of run time. Yet I ran it for 10 hours one day and 8 the next without recharging, plus a few hours  the day before that and for two more today before I screwed up and let my loads get out of balance, which ran my primaries down to 12.2 volts. And that doesn't count the inverter which is running off the system on which I have running 18.5 watts worth of lights the entire time.  And you can explain that all away through "desulfation" of the old batteries? Good luck with that.

[LibreEnergia]

We have three people in different parts of the country with working devices. All you have is your opinion. Either build it and see what it can do, or go away. I have no time for you. I am doing hours of test runs every day without ever charging the primaries. But just to annoy folks like you even more, I am going to the store tomorrow and buy two of the smallest amp hour 12 volt batteries I can find. My load doesn't change. It is a 12 volt motor that pulls 11 amps running another motor as generator. When I put a load on the generator it draws even MORE amps, but we won't go into that. The amp draw was taken with both an analogue gauge shown and a digital meter. It has been checked more than once and is ALWAYS at least 11 amps. Here is the video.


http://www.youtube.com/watch?v=xw5O5Cn7Nug[/font][/size]



Now, if I am not lying about that, how long would you expect I could run that load even if the voltage in all five of the batteries we are using in the system were full. We have three 18.5 amp hour batteries, one of which we drain down to 12 volts or less before putting it into the system. And we have two 4.5 amp hour DEAD batteries we are using as our transducer batteries which show less than 2 volts. So even if all of these were full, how many amp hours of run time could I expect to get out of my motor?
3x 18.5 = 55.5
2x 4.5 = 9
-----------------


65.5 amp hours


divided by 11 amps. is a little over five hours of run time. Yet I ran it for 10 hours one day and 8 the next without recharging, plus a few hours  the day before that and for two more today before I screwed up and let my loads get out of balance, which ran my primaries down to 12.2 volts. And that doesn't count the inverter which is running off the system on which I have running 18.5 watts worth of lights the entire time.  And you can explain that all away through "desulfation" of the old batteries? Good luck with that.

Before you waste any more time on this you should do as he suggests and try and run it on capacitors...
There is no excess energy being generated in your setup.

[markdansie]

Why build when over the years every single one of these devices I know that was tested failed to do as claimed. If you are so certain its not The battery effect then run it on capacitors. I owuld love to hear yoru argument on that.
Unfortunately history is against you on this and some well known examples like Magnacoaster has highlighted the folly. The last two I went to Test in South Africa both failed. Please name just one device (go to Free Energy News they have dozens listed) that panend out

measuring battery voltage is not a good indicator or the storage capacity or health , especially when your actually changing them.
@ profitis Care to design a set of tests and instrumentation for this to demonstrate it is anything other than the battery effect?
Kind Regards
Mark