NEW 180% EFFICIENT BI-TOROID TRANSFORMER

[CRANKYpants]

NEW BRIDGES MY-OVER-UNITY COUNTY...

DEAR ALL,

I HAVE UPLOADED THE NEW 1027% BI-TOROID PHOTO DATA HERE:
http://www.megaupload.com/?d=RY9LUR2V

Input voltage = 38.7 volts, current = 0.002 amps Pf = 0.88 / 28.8 degrees 
INPUT POWER = 0.07 watts
Load voltage = 8.5 volts LOAD POWER = 8.5^2/100.5 = 0.72 watts
Efficiency = 1027 %  (voltages recorded with true RMS meter).

CHEERIOS
Thane

[broli]

Forgive my ignorance but why did you not measure the current through the load. And what happens when increasing the input load, is there some sort of linear relationship or more of a saturating effect on the output.

[CRANKYpants]

Forgive my ignorance but why did you not measure the current through the load. And what happens when increasing the input load, is there some sort of linear relationship or more of a saturating effect on the output.

THIS IS A FIRST DRAFT - IT WAS JUST ASSEMLED TODAY.
INCREASING INPUT LOAD?

THE CURRENT THROUGH THE LOAD IS,

I = E/R
  = 8.5 / 100.5
I = 85.6 mA

POWER THROUGH THE LOAD IS THEREFORE,

P = I^2 R
   = O.0856^2 x 100.5
   = 0.72 WATTS

CHEERS
Thane

[alan]

I think he means really measuring it to rule errors out.

1000% efficiency, hope it is real 
(btw thanks for the PF explanation)

[CRANKYpants]

I think he means really measuring it to rule errors out.

1000% efficiency, hope it is real 
(btw thanks for the PF explanation)

MOST WELCOME,

JUST MEASURED IT WITH THE CURRENT METER TO DOUBLE CHECK FOR ACCURACY...
CURRENT THROUGH 100.5 ohm LOAD = 0.086 A OR 86 mA

THANKS
Thane