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Overunity Machines Forum



Hydrogen Only Electrolysis

Started by goldenequity, July 16, 2008, 05:20:45 PM

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0 Members and 2 Guests are viewing this topic.

slider1

I kind of agree, the Oxygen has to be oxidizing something. Being used in some kind of chemical reaction.

goldenequity

Here's what you are describing,
we have a "free" oxygen that is now unstable since having the hydrogen bond broken.
The hydrogen is offered an electron (to it's outer shell) by the negative electrode to stabilize it and so it breaks free as a gas.

Once freed, the oxygen is "looking" for an electron to share or tear away to complete it's outer shell and stabilize itself.
It will bond to whatever it is stronger than itself or tear apart whatever it is weaker than itself.... i.e. oxidation, reduction potential (ORP).

Normally, the positive electrode assists in the breaking of the water molecule bond by pulling (offering attraction to) the oxygen,
which tears the molecule apart, then offering it an electron to stabilize.

What you are describing is an electrode (aluminum) that "sacrifices" itself as a metal..... i.e. the oxygen has a stronger attraction to the electrons in the shells of the molecular structure of the aluminum .... and it starts to oxidize the metal to recombine as a metallic salt or an oxide compound.

Certainly, that is one possibility.  But that would be producing H2 ultimately through a chemical reaction which is done commonly.
There are many metallic compounds, when dissolved into water, change the ORP, break the water bond and release hydrogen.

The point is.... you don't need current or "artificial" electrolysis to do that.  I think something else may be going on here.

Without a sacrificing metal involved (one that cannot be "oxidized") the only course of action for the "free" oxygen,
would be to re-bond with the remaining water molecules forming hydrogen peroxide (H2O2) molecules.

That still leaves the mystery however of how you can have "enough" attraction for the oxygen on the one hand to "break" the water molecule in the first place, but still NOT offer the then "loose" oxygen anything stronger than the water itself to which it then recombines?  Quite a riddle.

It is however, what I think he is doing.  :)

slider1

I just doubt he is getting H2O2. IMHO

Bulbz

It seems to burn a lot slower thatn HHO, so it may be straight Hydrogen. But I also am thinking, one of the electrodes must be absorbing the Oxygen, and therefor must be decaying.
Best regards.
Steve Ancell.

goldenequity

Here is another video demonstration of his cell from March 22 this year.
http://au.youtube.com/watch?v=qPu6kdvX4ow

It would appear that he is electrolyzing ... i.e. no current = no gas  :o
also overdrives his cell (e-z to do with straight 12v DC into a small electrolytic cell)
it appears to start overheating and spitting water out his output hose.