improve torque idea

[ipower]

cause my poor english, i make a draw here,i think original newman motor need improve desigh so that it become small but high effective and strong torque, but how can we do ?
just share your thought.
some times newman motor very seems like a bendini motor.

thks

btw ,my new desigh model for more test use will be done next week .what's newman motor bring to me .?

[ipower]

today i change vltage to dual 12V, adjust brush design, the rotation speed
and torque increase but power input
reduce more,so surprise!! what happan?
first test:
12v 10ma =120mw
this test:
24v 2ma  =48mw

[kmarinas86]

today i change vltage to dual 12V, adjust brush design, the rotation speed
and torque increase but power input
reduce more,so surprise!! what happan?
first test:
12v 10ma =120mw
this test:
24v 2ma  =48mw

Doubling the voltage increases the rate at which the current rises. Also, your coil has a property called inductance.

Voltage/Inductance = Change in Current / Change in time + Current * Resistance / Inductance.

Voltage/Inductance is constant for a constant voltage.

What happened most likely is that when you doubled the voltage, your motor spun more than twice as fast. This is because the current rises twice as fast, allowing the torque to rise twice as fast.

Apparently, the drag on your motor less than doubled when you had the motor running with higher voltage. That is why you probably  observed twice as many pulses per unit time when you had the 24 volt setting than when you had the 12 volt setting. But the current then has less than 50% as much time to rise, so the current will average less than it did previously.

If you put stronger magnets on there, as well as a significant mechanical load, you should be able to see the same effect, with more torque and rpm, without changing the input voltage. Some people gave up when they saw their motor slow down when they added more magnets. Most likely however, they didn't have a mechanical load on it. So the top RPM of their motor fell, although their torque could easily make up for the difference in terms of mechanical power output. My older (smaller) motors had more RPM but way less torque, and addition, more of its energy was wasted on vibration. Bigger here is better.

Torque is transfer of angular momentum/unit time. Therefore, the rise of current resulting in a linear rise in torque amounts to an acceleration in the transfer of angular momentum, and is to power in the same way that torque is to energy. Since torque is change of energy per change in angle, change in torque per change in time is the change of power per change in angle (as a result of divided by time).

If you take change in torque / change in time (= change in power per change in angle) and multiply by angular velocity (= change in angle / change in time), you get change in power divided by change in time. If you integrate that with respect to the duration of time, you should get a value for power in that time that is higher in your 24 volt case then your 12 volt case. And also, if you integrate that with respect to time a second time, you should get a value that suggests more mechanical energy is produced in that period of time whenever change of power / change in time is higher. That is, for a given time:

(Change of power / Change in time) is proportional to (Change of energy / Change in time), or total power.

The current you should be drawing from the batteries should increase only in proportion to the change in current per change in time and fall inversely with how fast it is turning, provided that the rotary is efficient. The mechanical output power should rise proportionally to how fast energy stored in the coil is used to drive a mechanism (that is proportional to how fast the torque delivered to the rotor itself can rise***).

*** Torque in the magnetic field varies with its energy only by the tangent of the angle (this is because torque and energy only differ by a cross product and dot product respectively, as a product of coupled magnetic moments). As a result change of torque per change in time in electric motors is fundamentally the same as power, without regard to how fast the motor spins. Yet, the input energy is voltage times change of charge. The ratio of output to input therefore is (change in torque / (volt*change of charge*change of time)), and on a equal time basis, proportional to: (change in torque / utilization of electrostatic potential energy).

Fan motors in the market today are very efficient (joke  ). The reason why they can't be improved as much is that they already have high current densities (current divided by area cross-section of conductor), so increasing voltage is very dangerous with them. With Newman motors, we begin with ultra low current densities, which is the reason why they don't get hot. If you apply enough voltage to them however, they should beat most motors out there. And also, as a result having fine turns of wire, the production of eddy current drag in the Newman motor is very minimal, which is why it is relatively efficient despite the lack of axial symmetry in the magnetic coupling.

[Michelinho]

@ ipower

If you use a bigger and heavier rotor with a strong magnetic flux, your motor will run slower with more torque but will need high voltage and less current to run. When using high voltage as Newman do in his motors in a big coil, you use the extremely high bemf effect of surface supraconductivity to create a stronger magnetic field than what you supply to increase torque by an exponential factor. That is the Newman motor's secret. E=MC2 (L)


Take care,

Michel

[tagor]

you use the extremely high bemf effect of surface supraconductivity to create a stronger magnetic field than what you supply to increase torque by an exponential factor. That is the Newman motor's secret. E=MC2 (L)

bonjour  Michel

are you sure of that ?
have you a self runner of the  Newman motor's ?