Why a device need the 2 poles from the SAME battery?

[CTG Labs]

Hi Magnethos,

I think that before believing in Bearden it may help to learn and understand normal forms of electricity rather than jump in trying to find cold electricity which is essentially a an unproven idea.

When Bearden is talking about not destroying the dipole he means that you have a closed loop and you switch away before current flows.  Ie once you close a circuit, there is a small time after voltage is applied before current actually flows, this time gap however is extremely fast, faster than anything we have can switch at.  If you could switch that fast, you could switch away a potentialised circuit before you have any current flow and prevent the battery from running down.  Unfortunately it is not possible without slowing down this time period to something we can switch at.  But bear in mind, this is all just theory from Bearden, you must take it with a pinch of salt!

Regards,

Dave.

[captainpecan]

Your post got me brainstorming a bit...  Isn't it interesting how if you need to jumpstart your car battery, you can hook the black jumper cable to the frame of the car and still jumpstart it?!?!?!  Wouldn't that technically be an open circuit, since you only have the positive pole of the battery in the circuit?

Second thought... Since you can jump start a car with only the positive cable connected, wouldn't that mean you could theoretically charge a capacitor using only the positive, and not have a need for a diode? I'm almost positive I have tried this with a capacitor and it does not work, but now I'm wondering why it doesn't when thinking of the concepts of jump starting your car... Or does it work, and I did not do it right?

Just curious...  Any answers?

[WilbyInebriated]

the car's battery is also grounded to the frame so it is in actuality a closed circuit.

[captainpecan]

Good point... So doesn't that mean theoretically you could charge a capacitor if the negative was hooked into an earth ground?