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Overunity Machines Forum



Joule Thief

Started by Pirate88179, November 20, 2008, 03:07:58 AM

Previous topic - Next topic

0 Members and 6 Guests are viewing this topic.

detrix42

Quote from: Eastov on March 21, 2010, 07:15:47 PM
Dextrix,

   Here's another filament bulb JT circuit that I've been toying with, but mine a non-wireless version.  He's got a link in the description which shows schematics and details. 

http://www.youtube.com/watch?v=2ODW-ntPHSU

E

  That was pretty cool.  Great job.

detrix42

Quote from: jadaro2600 on March 21, 2010, 06:35:20 PM

You'll have to measure the ohmic resistance between the leads, there should be 6 leads, or Five leads and one ground. If there are four leads, then it shouldn't be a problem, you should also ask yourself why the power supply burned out?

Any two leads with an ohmic resistance are a coil, ..6 lead transformers are usually center tapped - this lead can be ignored if you want.  Using the two leads with the least ohmic resistance and the two leads with the most ohmic resistance will give you a voltage boost.

for instance, if there are 6 leads where there is ohmic resistance between 1 2 and 3, and the ohmic resistance of 1-2 is 20ohm, and 2-3 is 20 ohms, and 1-3 is 40 ohms, then pin 2 is the center tap.  Just as well of the other pins, if there is 40 ohms between 4-5 as well as 5-6, the pin 5 is center tap.

using pins 1 and 2 as the coil to base, and pins 4 and 6 as coil to collector will give you voltage boost because there are more windings on coil 4-5-6 than 1-2-3.  This will give you roughly voltage boost V ..while using pins 1 and 3 will give you voltage boost V/2.

IF you follow the diagram that I made for you on your thread, then you won't need a secondary, just a toroid and some mag wire, two capacitors and a resistor and a transistor.  You should not use the secondary, it's a waste of time for your particular circuit because it simply will not provide enough current between commutation switches.

In my schematic, the bulk of current will flow through the motor and not the transistor.  When skipping commutators, the transistor circuit will activate and produce a higher voltage, until it hits another commutator and discharges across the coil along with the current from the battery.

I tried measuring the pins, but this transformer is a bit weird.  Pictures below:
but I am only getting like .1 to .2 ohms between the pins even between the first and last pin on the 6 pin side.
I am not sure what the big white coated wire is exactly.

innovation_station

ok i have been unable to recharge my aa's properly as i cant find the wall charger .. 

so that inspired me to do this one ..  im almost done it .. 

im working on a aa charger ..  so far  really good ..  this is useing the coil showen in my last post .. 

it works well btw ... : )

1 2n222a 2 db107's 1 1k pot a lower power aa driveing it .. 

i can hear it when it is properly built and tuned out put is low .. i dont tap back side  at all on this unit ..

insted i force it out the 2 secondaries .. then to the db107's then into 3 aaa NI-MA 300MAH1.2V rechargable batteryies hooked up to supply 3.6 vdc per bridge

so there 6 aaa rechargables in this unit ..  they charge fast ..  really fast!   i then load the 3.6vdc down to a duracell aa rechargeable 1.2vdc 2650 mah for bout 1 min  then i breack the connection i watch my aaa climb back to 3.6vdc ... and i do it agin ... 

i need to automate the process ... it will stop and blink at .5 vdc in supply battery ..

as it is configured i would expect ma draw to be low ...

: )

ist!

to automate this im wondering .. if i could find a 5 volt relay and just add another battery  so when the bank has enough juice to fire the relay it dumps to the aa and when the bank gets too week to power the relay it breakes the connection ..  then repeates .. 

someone wanna help on that .. ? 


maybe ill just gang the outputs togather as 1  and recharge 12vdc ...aaa bank 2 feeds .. and then i can use the 2 wire electronic pulser to drain the 12vdc bank to the aa

: )

ill have to try it ..

To understand the action of the local condenser E in fig.2 let a single discharge be first considered. the discharge has 2 paths offered~~ one to the condenser E the other through the part L of the working circuit C. The part L  however  by virtue of its self induction  offers a strong opposition to such a sudden discharge  wile the condenser on the other hand offers no such opposition ......TESLA..

THE !STORE IS UP AND RUNNING ...  WE ARE TAKEING ORDERS ..  NOW ..   ISTEAM.CA   AND WE CAN AND WILL BUILD CUSTOM COILS ...  OF   LARGER  OUTPUT ...

CAN YOU SAY GOOD BYE TO YESTERDAY?!?!?!?!

Mk1

Quote from: detrix42 on March 21, 2010, 10:57:47 AM
thanks for that video link. Now to watch it a few hundred time to understand everything he is doing.

You may do that , but i can help ...
I also started a tread for it , feel free to ask questions.

http://www.overunity.com/index.php?topic=8878.0

@all

Hi everyone !

:)

Mark

crowclaw

Quote from: detrix42 on March 21, 2010, 04:14:57 PM
I am trying to look up a transformer that I pulled out of that power supply. I did a google search and found nothing.  the numbers on it are   --  6C03313120 MORETEC 99235C.  How do I get a pin diagram for it???

Hi detrix,
Doubtfull if you will get a schematic for your TX. Try this site:http://www.smps.us/computer-power-supply.html .... may help. If you have a multimeter it will help identify the windings, the resistances will be quite low.