Joule Thief

[jadaro2600]

I hate to be a dragging poster, but..yet another thought on the blocking oscillator action.

Doesn't the fact that a switched on transistor pose a path of less resistance to ground, wouldn't the transistor being 'on' cause less energy to flow through the path to the base based purely upon fundamentals of the electricity wanting to take the path of least resistance?

It was pointed out that inductance and resistance aren't as alike I a once thought they were, this is now obvious to me,  , they can be looked at similarly, but only to a certain degree.  In some situation, a large inductance may behave like a non ohmic resistor with a time derived resistance - like a bell curve of sorts?  All true ohmic resistors dissipate heat ( losses ).

I apologize for my non-tradition electronics perspectives, I have on hobby background in these matters.

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I guess one way to test the idea would be to completely remove the ability for the inductive forces impeding current flow in the base coil from that of the collector coil..and simply have them not interact.  For instance by completely removing the coil to the base, and see what happens when they share a source voltage and current...  which I'm off to do right now.

*edit, maybe I should just go take a course.   ..this didn't pan out at all,

[jeanna]

OK Mark,

(I must quickly write this before I lose the picture in my head.)

As it appears to me, the energy coming out of the AC part of the bridge is actually used for a load of some kind.

The rectified part that is coming off the dc of the bridge is sent back into the jt coils.

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I don't have 120 volts coming from mine. Are you saying I can feed them both back into the jt for another boost? Or is feeding the DC part enough?

I would think it would be.
But I am really new at this electronics stuff. wow.

thank you,

jeanna

[Mk1]

OK Mark,

(I must quickly write this before I lose the picture in my head.)

As it appears to me, the energy coming out of the AC part of the bridge is actually used for a load of some kind.

The rectified part that is coming off the dc of the bridge is sent back into the jt coils.

--
I don't have 120 volts coming from mine. Are you saying I can feed them both back into the jt for another boost? Or is feeding the DC part enough?

I would think it would be.
But I am really new at this electronics stuff. wow.

thank you,

jeanna

On the mk2 there are 4 pickup coils ABCD , the positive from one pair AC is send back to the other pair BD.

[jeanna]

On the mk2 there are 4 pickup coils ABCD , the positive from one pair AC is send back to the other pair BD.

First, I connect A and C so not to cancel the voltage. This longer wire becomes A-C.
I repeat this with B and D this becomes B-D

I am understanding that only one of these pairs is rectified B-D

A-C is still oscillating. Is it not?

jeanna

[xee2]

@ jadaro2600

Equivalent JT circuit. Transistor works as switch. Base coil is just to turn transistor on and off. Try it.