Low Current HHO Production.

[mscoffman]

a dipole can be tuned to resonance using a grid dip ocsillator.
this small device will put a signal into the dipole, in this case 42.854khz. the grid dip oscillator has a tuning capacitor on it that allows you to tune to the dipole. this will indicate if you have either to many or not enough windings on the dipole.

if the oscillator is set to 42.854khz exactly and the dipole is resonant the meter on the grid dip oscillator reads zero. this shows that there is no feedback or harmonics being returned. using this method you get maximum energy transfer.

a dipole of this size is dangerous especially at these frequencies. just 10wats into this dipole could cause stinging in the eyes and also rf burns.
1000watts could do major damage to a person. it must therefore be protected inside a faraday cage while switched on.

I agree with the above.

---

Ok...with transmitter induced LC resonance the voltage on the antenna is likely to be a whole
lot more than 12Vdc. More likely 250Vac as the voltage/current waveform rings in the LC as it
is being pumped up. It would be interesting to use a VSWR virtual standing wave ratio, meter
on the transducer. It would show how much power is being pumped back and forth vs how much
power is being absorbed into the water as a percentage of total power. The water probably
spits a lot of power back out as it vibrates ~ whatever component of the water that is doing
the vibrating.

So I don't think the 4.4 amps can be added to the to the other 12volt amperages. You really
need to add wattages but I realize how other HHO people calculate totally based in 12Vdc. The
thing is probably overunity in either case anyway.

:S:MarkSCoffman

[Hydro-Cell]

i havnt done the math yet on the voltage of the wave produced peak to peak but it is probably very big.
on the vswr it is showing no reflected power back to the electronics powering the dipole.

the coil has been tuned to presicion and a lot of time has been spent to squeze ever last bit of power out of it. its tuning of the coil is spot on to the frequency required. the swr is spot on with no reflected power, so all the power goes to the dipole and is radiated.

when a radio wave such as this passes through an object it resonates at that frequency. the part of the molecule that is targeted is the covelant bond. this will be resonant to the frequency induced and will gradually resonate itself to distruction if given enough power.

the idea is that as the bond stretches it becomes weak the now weak bond requires less power to break it into its seperate atom by also inducing harmonics into the plates in the water the resonant frequency is strengthened.

i have further ideas that the temperature of the water will play a major part in this resonance feature. i have yet to experiment with this though as i am currently building a unit to set the temp of the water to be pumped through the cell.

the ultimate goal is that the cell becomes a unit that can vary its output simply by adjusting the input voltage. that way if more gas is required simply turn the dial, however i feel that there wil most definatly be an optimal setting.

[TinselKoala]

please read previous posts, the maths do the talking the formula according to ohms law is

power in watts / ohms squared

1000 watts / 50 ohm output = 20
square root of 20 = 4.4

simple. the other way i know im getting 1000 watts to the load is that im using a 1200watt amplifier at near full power

In your first post you say:
"i have 1000watts of power going into this dipole. this consumes only 4.4 amps of power."
In a somewhat later post you say "all at 12 volts"

There is no way that you are getting 1000 watts of continuous RF power out of an amplifier or transmitter drawing 4.4 amps at 12 volts.
This is a remarkable claim and I'd like to see some justification for it.

You can wave all the math around that you want, but unless you show where your input numbers are coming from, it's just so much hand waving.

[Hydro-Cell]

hi tinselkoala

ok here goes this is the setup....in this order...

12 volt car battery,...this powers the following

1 frequency generator and a 12volt amplifier @ 1200watts

so the frequency generator goes onto the amplifier and after the amplifier we have a matching transformer that goes from 8ohm impedance to 50ohm impedance.
after this we have a band pass filter with centre frequency of 43khz and 30khz bandwidth.
connected to the bandpass filter we have the dipole.

now since we have increased the impedance of the output to the amplifier this in turn takes load off the electronics and we also get full power transfer from the amplifier to the dipole. this power could be a peak to peak voltage in the hundreds of volts ac. but as far as i am concerned as you can tell by the description the system uses 12volts to drive itself.

it works in the same way as a car, your car works on 13.8 volts do you really care that it actually take 30,000 volts to get the plugs to spark???
you dont say "oh my car rns on 30,000 volts because it doesnt, the electronics etc convert the power.

the laws of thremodynamics are correct, energy cannot be made nor destroyed, only converted.

12volts in is 12volts in where else can the power come from??

[TinselKoala]

And when you hook an ammeter in series with the 12 volt power supply and the 1200 watt amplifier while it is running and powering the load, it is reading 4.4 amps. Am I understanding that right?