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Overunity Machines Forum



Fusionchip's Bedini Feedback to Source!!!

Started by Goat, January 09, 2009, 11:54:12 AM

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0 Members and 4 Guests are viewing this topic.

gadgetmall

Although Comworrier69 is not attaining Ou  because of his  various test mods to My Circuit and Claim  . I achieve much better cop . probably COP 1-2  where as his replication is not using the Transistor and rectifiers nor the 48 volt fan  i  discovered the transistor breaks down on the Off Cycle of transistor because  of and High Bemf is triggering the base and leaking back thru the transistor in reverse .I am only Guessing but it is obvious to me that would be the only way the circuit will actually charge the battery  Hv is taking the path of least resistance which would be from the collector thur the emmiter thru the battery negative and return to the coil . The Voltage drop of My Diodes are much less than .5volts where his is 1.5 volts i believe he said ?
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plengo

some updates. I am running now with the FAN spinning. Target current is under 8ma (around 6 to 7.5 ma)  because it seams that my 100amp/h battery is not that conditioned as gadgetmall is. I used this battery for my 200 load tests SSG Bedini circuit last year during the Monopole3 staging process so it somehow conditioned but not enough yet.

After running this for the last 12 hours it is very clear to me that it is possible to have the radiant spike generate enough positive electricity to run the FAN and keep the battery voltage level steady or even increase. Also as it runs I can also see that the battery is only getting better at it.

Now, I have the fan spinning at around 264 rpm and it is creating about 700 pulses or radiant spikes per rotation plus the two reciprocal waves I shown on previous posts. The battery is still running down about .01v every 3 hours or so, BUT, if I disconnect the circuit and wait 2 to 5 minutes max and connect it again the voltage is back to where It was when I started. I have been doing this process the whole day and the battery is still sitting at the same voltage of this morning and the FAN is spinning constantly.

So rough calculation of 7ma average at 12.10v for 12 hours gives me 1 watt/hour roughly (please correct my bad calculations anyone :) ). It is not much but it is enough to see it dropping the voltage of this particular battery during tests.

Tunning the resistor at the base of the transistor is the the most tedious step because one has to wait and see if the fan will not accelerate too much and use too much current or slowly reduce speed until stops which could be around 5 or 10 minutes later. It seams that I got the correct setting that balances the weight of the fan, its speed and current consumption at its minimum to a perfect balance. I also removed the capacitor C2 (the one that receives the spikes) so that the spikes goes directly to the battery without being converted into positive electricity first.

I can, based on my data so far, see how much possible is in having a very well conditioned battery (such as gadgetmall's battery apparently) to not only run this but also charge as it receives the radiant spikes, may be even to the point of increasing the current consumption to above 8ma possibly 20ma. BTW at 20ma you will have the FAN spinning at 1500 rpm easily.

@gadgetmall

would be possible for you to give more accurate info about the current consumption you have and speed of the fan? would be possible to make a new video showing closely the SOUND of that fan pulsating (for me it would tell a lot because I can tune my fan by the sound of its pulses)? Also could you tell me the exact resistance you have on the pot when you have the system well tune? and the correct capacitor value on the base of the transistor?

@ALL,

for those that are still not believing this, I highly would advice spending some time on this little circuit because it is really tricky but definitely possible to have it running at least in oscilation mode and charging a battery at the same time. The 48volts fan is very cheap (gadgetmall showed a link to a seller a few pages before). I got 3 for the total of $12 including shipping.

There is definitely something going on here and it is not a matter of too big battery or faulty measurements, or not knowing how to measure input versus output, no, this can not get simpler than it is. Get a regular small 12 volts wet lead acid battery. Smaller better so you can see the results faster. SLAs or GEL cells WILL NOT WORK. They simply dry up with radiant spikes ( I already destroyed 4 of those ).

There is not need to measure the input versus output really because both are one and the same, the perfect closed loop perpertual circuit that we ALL are looking for. No need to worry about those RF signals and their difficulty with DMMs and all that sweet talk I hear in every thread. All one needs is patience and some multimeters to measure the drop of the voltage as you run the circuit on a day or few days. It does not matter if even in the end you have only ghost voltage on the battery as long as the fan is spinning and the voltage does not drop by the end of the day!

It would really be good to have some good brains here with time in their hands. If this is really what I am seeing there is a great potentitial because Bedini has already shown the level of scalability his monopole got (in his EFV DVD he has one running and generating about 1200 watts of power). So, this circuit is pretty much the same as Bedini's SSG therefore scalable.

Fausto.

hartiberlin

Hi Fausto,
nice results.

But 7 mA are not much for a big 12 Volts battery.
So as batteries are very nonlinear with their voltage to
charge state, maybe try to measure the gravitation
of the acid with an gravitation meter.
So you can see, if it will get less charged over a few days.

Yes you are correct in 12 hours you have drawn about 1 Watthours
of energy from the battery and you still say, that it has dropped its voltage,
but surely this is a way to use batteries much longer, small currents and
use the radiant spike recharge effect.

Maybe you are also using this way stimulated radioactive decay as some lead isotopes radiate some
beta decay and thus increase the battery energy ?
Could be.

Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum

plengo

@hartiberlin
very interesting this Daniel guy. Do you have any more info about him and his shows?

@ALL

my test circuit is attached. It has been running since last morning with NO voltage drop whatsoever. A steady 266 rpm and 7.8ma average consumption. Signal is still the same as before with about 700 pulses per magnet pass plus the two reciprocal waves. I added a capacitor cross the emittor/collector of the transistor pnp 3904. I also removed the 470uf 200v capacitor that gadgetmall inserted to let the radiant spikes to go directly to the battery ( I think I stated that already before ).

I am very , very, very happy that for a full 48 hours my battery has not changed its voltage at all despite the 7ma consumption. This battery is actually a 795 cold cranking amps battery (I have no idea how much is that in amp/hours really, I just thought my battery was a 100amp/hour for some strange reason). I know that 7ma this battery can go on for a long time, BUT i have also done over 200 load tests on this baby and I KNOW even with this small current I can change its voltage to one tenth of a volt in about 2 or 3 hours easily on 7ma. SO, it is working somehow.

We will see if it will stand the time. I think if it runs like this for one week there will be no doubt this is really indeed regenerating its own power.

I have to buy a very small wet lead acid battery but I could not find one in the net. If anyone know where I can buy one cheap that is around 2 to 5 amp/hours max it would be great so that I can test this more speedly.

Fausto.

hartiberlin

Hi Fausto,
try to use ba faster diode instead of the 1N4007,
better also use a 1N5408, cause they will conduct
the radiant spikes much faster.

The 1N4007 are only good for low frequency applications
like 50 / 60 Hz systems...


Regarding the Pomerleau PDF file from
Laurent: semda@free.fr

He wrote to me:

See the PDF file.
If you discribe this system with 2 equations (one for 1=Serial LRC and another
for 2=Paralel RLC WITH the interaction by Capacitor and by coil, you will see
that in the loop RL of 2 you can have PERMANENT CURENT (AC or DC) witch works
WITHOUT battery. By a similar interaction system, atoms works in permanent mode,
and supraconductivity works in permanent mode with cooper par.
Stefan Hartmann, Moderator of the overunity.com forum