ENERGY AMPLIFICATION

Tito L. Oracion · July 24, 2014, 12:12:44 AM

lancaIV · July 24, 2014, 02:48:18 AM

ENERGY AMPLIFICATION = ENERGY CELERATION
ac-/de-
catalysis
cata~genesis/ (e-)volution

f.e.: rotatory
http://peswiki.com/index.php/OS:Rotoverter

Cutting the Voltage in half also cuts the current in half, which cuts the Power input by 75%!
VOLTAGE CELERATION is ( VOLTAGE + CURRENT ) CELERATION

( Once the motor is Power Factor Corrected for this voltage, the motor will appear to run on NEARLY NOTHING!!!! And of course, that is the point.)

http://worldwide.espacenet.com/publicationDetails/description?CC=DE&NR=2733719A1&KC=A1&FT=D&ND=3&date=19790215&DB=EPODOC&locale=en_EP

Mukherjee Rotoverter,first published 1977

Durch das Magnetfeld der elektrischen Einrichtung fliesst infolge der Leiter an dem Anker in der gewünschten Richtung ein einseitig gerichteter Strom, wodurch auf den Anker durch sein Magnetfeld und somit auf die Welle fortlaufend eine Kraft ausgeübt wird, die die von dem Generator ausgeübte Gegenkraft kompensiert.[/font]Wenn bei einem herkömmlichen Generator die Feldstärke B, die Länge seiner Leiter mit L und der durchfliessende Strom mit I bezeichnet wird, ergibt sich die Grösse der Gegenkraft F, die auf den Leiter und somit auf die Welle ausgeübt wird zu F = BLI.Wenn die Feldstärke der elektrischen Einrichtung 2B, die Länge seines Leiters L beträgt und nur ein Strom durchfiiesst, dessen Stärke der Hälfte des im Generator fliessenden Stroms entspricht, beträgt die auf den Anker ausgeübte Kraft F' = 2B x L x 1 = LI. 2 Dies zeigt, dass die auf den Anker der elektrischen Einrichtung und somit auf die treibende Welle ausgeübte Kraft gleich der Gegenkraft ist, die auf die Welle von dem herkömmlichen Generator ausgeübt wird. Die Kraft wird erzeugt, dass sie in einer solchen Richtung wirkt, dass sie die Gegenkraft kompensiert. Ein etwas stärkerer Stromfluss sorgt für das erforderliche Drehmoment an der Welle. Deshalb werden die Welle und somit der Anker weiterbewegt und elektrische Energie erzeugt.Um diesen halben Strom durch die elektrische Einrichtung fliessen zu lassen, ist die Hälfte der Generatorspannung erforderlich. So mit wird 1/4 der erzeugten Leistung verloren, um der Verzögerungskraft engegenzuwirken. Die verbleibenden 3/4 der erzeugten Energie bzw. etwas weniger davon stehen für den Aussenverbrauch zur Verfügung.Wenn die Feldstärke der elektrischen Einrichtung ein Vielfaches der Feldstärke des Generators beträgt, beispielsweise das 5-Fache, ist es erforderlich, dass 1/5 des erzeugten Stroms in der elektrischen Einrichtung fliesst, um die kompensierende Kraft zu erzeugen. 1/5 der erzeugten Spannung ist dabei für den Stromfluss erforderlich. Somit wird 1/25 oder 4% der erzeugten Energie in der elektrischen Einrichtung verbraucht, während 96% oder etwas weniger davon für den Aussenverbrauch zur Verfügung stehen. Auf diese Weise ist es nicht erforderlich, dass irgendeine elektrische Energie von einer externen Quelle in den Generator gemäss der Erfindung zur Erzeugung von elektrischer Energie eingeführt wird.

partial Mukherjee Rotoverter description

Saxonian 2 Anglo-Saxonian translatory :

By the magnetic field of the electrical device to flow due to the head of the anchor in the desired direction is a unidirectional flow, thereby continuously exerting a force on the armature by means of its magnetic field and therefore to the shaft, which compensates for the force exerted by the generator counterforce. in a conventional generator, the field strength B, the length of its conductor L and the current flowing through is denoted I, the result is the size of the reaction force F which is exerted on the conductor and thus to the shaft to F = BLI ., if the field strength of the electric apparatus 2B, the length of his head is L and only one current durchfiiesst, corresponds to the thickness of half of the current flowing in the generator current, is the force exerted on the armature force F '= 2B x L x 1 = LI. 2 This shows that the force exerted on the armature of the electrical device, and thus the driving shaft of the motor is equal to counter force which will be exerted on the shaft from the conventional generator. The force is generated to act in a direction such that it compensates the reaction force. A stronger current flow provides the required torque to the shaft. Therefore, the shaft, and hence the armature continues to move and allow electrical energy to flow erzeugt.Um half this current flows through the electrical device, the half of the voltage generator is required. So with is 1/4 of the power generated is lost to engegenzuwirken the retarding force. The remaining 3/4 of the energy generated, or slightly less of it available for outdoor use for Verfügung.

Wenn the field strength of the electrical device is a multiple of the field strength of the generator, for example, 5 times, it is necessary that 1/5 of the produced current flows in the electrical device in order to generate the compensating force. 1/5 of the generated voltage is required for the current flow. Thus, 1/25 or 4% of the energy produced is consumed in the electric device, while 96% or less of which are for outdoor use are available.

In this way it is not necessary that any electrical energy from an external source is introduced into the generator according to the invention for generating electric energy.

q.e.d. ,the overunity-formula abstracts and concrets

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relatively cheap rotoverter mosaic object fabrication,open source :
http://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=1&ND=5&adjacent=true&FT=D&date=19940614&CC=US&NR=5319844A&KC=A

5hp/lbs power/material density

the vision :
the 10 US$/ KW revolving e-gas-turbine

like Roy Kessinger,Lynx Motion Technology, "low cost" prophecy :
http://www.katech.com/katfiles/people.html

as dynamoelectric multi-slice-motor and as multi-slice-generator
with production costs going down to 5US$/hp

and Reinhardts ex-spectation about Co-Gen costs:
http://www.greencarcongress.com/2009/04/concept-compact-twocycle-cogenerating-pistondriven-turbine-to-deliver-60-efficiency.html :

The Reinhardt Turbine is designed to be compact, cost-effective and easy to manufacture. Andrews estimates that the manufactured cost per kW will be less than $10, so a 30 kW engine would cost around $300

Have a good day
OCWL

p.s.: alternatively ram pump ( in memoriam Toribio Bellocq )
http://www.rexresearch.com/Kutienkov/kutienkov.htm

Cost of used materials and manufacturing from them details for the given generator, as claim its developers,does not exceed 10EUR/kW.

10 EUR/KW ,
the aristocratic Bench-Mark
10 US$/KW

1Cent/Wp-Nantennas and Nano-machines :

http://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=11&ND=3&adjacent=true&locale=en_EP&FT=D&date=19860304&CC=US&NR=4574161A&KC=A
Polarizing sheets are now articles commercially manufactured by a bulk process at low cost by a large scale special film casting machine, the basic cost being about $1 per m@2 (1984 dollars). The present invention utilizes a similar bulk process. The casting composition@3 is modified to employ the special heteropolymer of this invention made on a similar casting machine@4. The cost should be comparable. The extra cost of electroding and laminating will add only a few dollars per m@2 so the total should be about $5/m@2 (500 w), about 50.cent./sq. ft. The efficiency will remain in the 60-80% range. Thus solar energy will become available everywhere at about 1.cent./watt; or, an investment cost of $10/KW.

http://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=0&ND=3&adjacent=true&locale=en_EP&FT=D&date=19941018&CC=US&NR=5356484A&KC=A

The reversible thermoelectric converter used as a heat pump differs from the use of the reversible thermoelectric converter for power conversion in that means is used to reverse the current through the diodes 10 and 20. Current reversal can be obtained by applying a voltage from a DC source 52 between the output terminals 14 and 24. Alternatively, a voltage can be applied between the terminals of diode 20 to obtain current reversal. The current reversal occurs when the voltage applied by DC source 52 has a larger magnitude and opposite polarity as compared with the open circuit output voltage of the reversible thermoelectric converter. The ratio of the open circuit voltage to the contact potential across the diode electrodes is given by (Tr /Tc -1).[/font]The reversible thermoelectric converter shown in FIG. 1 can be used to provide an AC power output. For AC operation, the current through the reversible thermoelectric converter is reversed cyclically so that the converter generates a cyclic electric or thermal power output. A cyclic input can be applied between the terminals 22 and 24 of the cold diode 20 so as to generate a cyclic output with the same waveform as the input. The frequency of the cyclic output power can be as great as the frequency corresponding to the relaxation time of the reversible thermoelectric converter, which can be less than 10@-14 second. When a cyclic or AC input is used, the reversible thermoelectric converter can function as an amplifier.Use of the reversible thermoelectric converter as an amplifier is shown schematically in FIG. 7. An AC signal Pin is applied to quantum well diode 20 at a low temperature Tc and input thermal energy is applied to quantum well diode 10 at a high temperature Tr. The AC signal Pin can be in the form of thermal energy, such as optical photons, or in the form of electric energy, such as a voltage applied across terminals 22 and 24 of diode 20. The output electric energy Pout is an AC signal with the waveform of the input signal Pin. The amplification factor is given by (Tr@2 /Tc@2)-1, where the input AC signal is applied to the cold diode at temperature Tc in the form of thermal or electrical energy.By way of example, an input signal of 6 microwatts with a bandwidth of 1 gigahertz is applied to diode 20 either as thermal energy or electric energy, and thermal energy is applied to diode 10. A signal-to-noise ration of 60 dB is obtained for the input signal for a temperature Tc of the cold diode 20 of 300 DEG K. For a temperature Tr of hot electrons in diode 10 of 6000 DEG K., the amplification of the input signal is 26 dB, which gives an output signal of 2.4 milliwatts. The amplified output signal also has a 60 dB signal-to-noise ratio.Use of the reversible thermoelectric converter as a refrigerator is shown in FIG. 8. In this case, thermal energy is transferred out of a low temperature region 54 at temperature Tc containing quantum well diode 20, and thermal energy is given off by quantum well diode 10 at a higher temperature Tr. A DC source 56 connected between output terminals 14 and 24 causes the normal direction of current in the reversible thermoelectric converter to be reversed, as described above in connection with the heat pump of FIG. 6. The refrigeration cycle shown in FIG. 8 is similar in concept to the heat pump cycle shown in FIG. 6 and described above.The quantum well structure in the quantum well diode contains the thermal energy of the hot electrons throughout the period of time required for the input thermal energy to be converted to electric energy by reversible electron transitions between energy levels. The quantum well diode serves a similar function for the heat pump process. The elimination of the requirement for a separate thermal barrier in the reversible thermoelectric converter of the present invention permits low cost, state of the art fabrication of the converter from thin films of common materials such as, for example, copper and aluminum.
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In the nonplanar reversible thermoelectric converter of FIG. 10, electrode 136 can be a 100 angstrom evaporated copper film, barrier layer 140 can be a 12 angstrom evaporated aluminum oxide film, electrode 138 can be a 140 angstrom evaporated aluminum film, barrier layer 148 can be a 700 angstrom deposited indium tin oxide transparent conducting film, electrode 142 can be a 280 angstrom evaporated aluminum film, barrier layer 146 can be a 12 angstrom evaporated aluminum oxide film and electrode 144 can be a 140 angstrom evaporated copper film. Terminal 154 is typically connected to terminal 156. For this embodiment of the invention, 1 kilowatt of output power is available per square centimeter of active area of the quantum well diodes.
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Who understands the rotoverter principle,the Diods/Condensator/Capacitor use function
and the Joseph Yater nanoscale reversible heat-refrigeration-pump and nano-scale thermal-noise/voltaic amplifier function will now not more have logical resistances to understand this micro-scale amplifier concept:

http://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=2&ND=3&adjacent=true&locale=en_EP&FT=D&date=19940318&CC=FR&NR=2695768A3&KC=A3

( and will also find calculating errors : the given example not near 11 KW,but more in the 3KW range)

dllabarre · July 24, 2014, 07:08:44 AM

Quote from: Dave45 on July 23, 2014, 10:15:52 PM
Hey Bob
I must have missed that post somehow.
A very interesting read on the WFC and Tesla choke.

A few months back I ran across V8carlos's work,
He used a bifilar primary, pulsed one winding and ran the bemf from that winding into the other winding and reported overunity results.
He put out a pdf this is the schematic from that pdf.

Do you have a link to V8carlos' pdf?ThanksDonL

Dave45 · July 24, 2014, 07:44:32 AM

I saved it, let me see if I can upload it.
Not sure how to upload pdf files.

Do a search for V8karlos on this forum, he came here in 2012, got ran off by the "know it all's" on this forum.

Dave45 · July 24, 2014, 08:19:10 AM

Non inverted buck boost converter using separate chokes

ENERGY AMPLIFICATION

Tito L. Oracion

lancaIV

dllabarre

Dave45

Dave45