ENERGY AMPLIFICATION

[Magluvin]

  No...  No free lunch in the real world. As free energy is killed by each and every component used. The more of them the less for us. Right?  So how do we get to OU. Remember OU...   As an old timer here, you should know how, by now. But, no...

In the strange case of cap to cap, of which you will not see in any circuits ever, Im just saying that whether we use that transfer to do something, or whether it were an ideal world where the energy IS just lost no matter what, then anything we do with that transfer is free in a sense. The idea of my findings is that here we do have a case where energy was not converted to another form when it came to the ideal format. I find it to be a very interesting example and want people to realize what is actually going on when ever they run across this problem in the future.

Mags

[Magluvin]

In the strange case of cap to cap, of which you will not see in any circuits ever, Im just saying that whether we use that transfer to do something, or whether it were an ideal world where the energy IS just lost no matter what, then anything we do with that transfer is free in a sense. The idea of my findings is that here we do have a case where energy was not converted to another form when it came to the ideal format. I find it to be a very interesting example and want people to realize what is actually going on when ever they run across this problem in the future.

Mags

Like this.  If we have a real superconducting setup of the cap to cap, and we still lose 50% in the action and the energy did not convert to another form, then we should be able to say that we can create energy from nothing in a way. May be a better way of saying it, but you get my drift.  Just promoting a bit of hope.

Mags

[WhatIsIt]

That is 50% losses for 2 caps.

If we have 1x100uF, 20V and 10x100uF empty caps,
in each empty cap will be loss of 50%??? , 10x50% loss, if we try to equalize them parallel.
At the end empty parallel caps will eat all the energy from first one in the way you describe.
Is that so?
How much energy will remain in that case?

If I start with 100uF, 20V and I end up with 100uF, 20V, I will lost 50% of energy no matter that
values on the start and end are same?

So start 100uF, 20V and end 100uf, 20V does not contain same energy?

You are dividing 20 / 4 = 5
but then you adding 5 + 5 = 10 to get on the same point you started (20)
Can you mix operators ( * and / ) with ( + and - ) , because they are not the same order.

OF course, answer is, I don't know basic math.
For you 100uF, 20V and second caps serial 2x100uF, 10V (100uF, 20V in series) does not contain same energy?

But if you use step down transformer from 1A, 100V to 2A, 50V the energy is same (power)?
So in transformers it is the same, just in caps are not?

If you say so, then it must be true.

[WhatIsIt]

If that what you say is true then if we double voltage on cap,
we should expect 4 times the energy?

Stick has two ends, so it can work in other way too...

Example:
We have 100uF, 20V and we raise voltage to 40V, then we have
100uF, 40V and 4 times larger energy?

Then it is not needed to search for free energy, this is solution,
just raise voltage in cap and energy is limitless.

Good luck with that.

[WhatIsIt]

Your great knowledge comes from Wikipedia which says Q/2 and V/2,
and you accepted that without thinking.

In our case there is NO Q/2,
there is just V/2.
Our capacitors did not change capacity, they remained 100uF at the start,
just as they were 100uF at the end.

No capacity change, so Q/2 can not be applied.
There is only voltage change.
Capacity of 2 capacitors remains constant, 100uF.

Nobody ever said nothing about capacity change, none.

Can you understand there is no change in capacity in our capacitors?

There is no conundrum.
For this case there is only law of parallel and serial capacitors connection with constant capacitance of 100uF.

Electricity is not water, but caps are containers.
From 1 liter of gas at 10 psi, you can get 2 liter at 5 psi of gas if the volume of containers are equal,
but you can not do it with water. Water can not be pressed.
Analogy of gas pressure and volumes is more closely to our capacitors and voltage analogy then water analogy.
Voltage is pressure which can press charges close to each other with increase of voltage.

Otherwise, parallel and serial connection law would not work,
and we will have major violation of that laws,
laws which happened to be true for a long time,
and not from yesterday.