Are Tommey Reed´s pulse motor circuits overunity ?

[chrisC]

I really don't want us to get out of control, But some things I know very little about. Its seem that everyone has a higher degree then I do. As a high school drop out, I had to go and work to help my family out and buy my own things i needed, because we where poor.
But that my past, as for know I do listen and hear what people say.
Its hard to say OVERUNITY, but every test I have done with no back ground in schooling is showing higher output then input at different testing stage.
I have no problem if I'm wrong, but nobody has really prove it yet.
Not to bash gotoluc, but I did show his calculation was off when using capacitor to disprove the output.

Tom...

Hi Tom:

Let me assure you NOBODY knows everything except almighty God and the 'wise' are really foolish! (1 Corinthians 1:27).
You've been trying to do good stuff and please do continue. Good people like you are honest and try their best to make the world a better place. You may not know everything but at least you're prepared to learn and you've come a long way from not being schooled like some of these 'degreed' people who can only point fingers! I'm sorry I currently don't have time to follow your project.

cheers
chrisC

[Cap-Z-ro]

Tommy,

You are certainly not wasting your time here...I and many more have been inspired by what you are doing.

I'm not qualified to determine whether your circuit is OU, but I hope you are right...nevertheless you just never know what your work will lead to, rolling around in a fertile mind.

I would stick mainly to instructing though...debating wears on you after a while.


Regards...

[gotoluc]

Not to bash gotoluc, but I did show his calculation was off when using capacitor to disprove the output.

Tom...

Hi Tommey,

please do understand that my video was not to discredit your research in any way as I am also a high school dropout at 16 and worked my way through life. I'm now 47 and 2 weeks ago became a grand father to my sons newborn son.
For the past 2 years I have been working full time in research to alternative Free Energy solution with zero income. For the past year I have experimenting with what you are doing now and I still cannot claim Over Unity

My video was to help you and show a different way to calculate energy in and out.
You now understand it but you still need to understand the correct way to calculate capacitor energy. I also thought I had reached Over Unity last year until someone posted that I was not calculating it correctly.

Here is a great online capacitor energy calculator: http://www.electronics2000.co.uk/calc/capacitor-charge-calculator.php

23,000uf at 12.3vdc = 1.74 Joule energy

23,000uf at 6.6vdc = .500 Joule energy X 2 = 1 Joule

To reach Unity you would need both caps to be at 8.70vdc = .870 Joule X 2 = 1.74

I hope this can help you I also hope you keep up this great research as we need more of us working together at real testing like you are doing to find the best answers.

Luc

[Tommey Reed]

What I do understand is when I showed everyone that when you charge a capacitor with a battery and use that charge cap to charge another cap with the same rating, there is a lost of energy.
When I showed the test with my pulse generator using the capacitor as the battery to charge the other cap, It show more energy then the battery test.
I have come to this point that Its a waste of my time to comment any more...........
I have disprove the capacitor test and now people are saying its not 600% overyunity, and yet buy charging the caps to get higher readings then a basic battery test , this means nothing?
You people wont even aprove 110% effieiency if it was in your face, so Its time to move away from the so called OU group!
I will stop wasting your time, I know I'm not the first to leave.........

I have better things to do then sit on my butt and talk trash........

[Ergo]

Here's another one for Tommey and Gotoluc. How to truly measure efficiency.

In Gotoluc's lamp test video he didn't consider the effect of wattage, which is voltage times current.

The output lamp was brighter, yes that's a fact, but current alone does not show true power.
The output was a steady 1.88 Volts at unknown current that lit the lamp.
If we assume there was 100mA of output currents this equals to 0.1A * 1.88V = 0.188 watts.
This is a pretty good estimate considering how weak the lamp was lit.

The input lamp was not lit, BUT there was 12.34V available from the battery. That's a lot more than 1.88V
Due to the lamp not being lit we know the input currents to be less than the output currents.
If we assume there was 20mA of input currents this equals to 0.02A * 12.34V = 0.2468 watts.

The efficiency: 0.188W / 0.2468W = 0.76%. (My estimate actually matches the efficiency of iron very well)

In this simple case it shows you that you can't use series connected lamps as a measurement tool.
When taking measurements you need to take voltage x currents in calculation. That gives you wattage.
The input lamp was not lit, but the total power input was higher due to you having a high input voltage.
Don't forget. Voltage x Current = Watts. This is crucial to understand.
Always take measurements in Wattage or Joules when checking a system. A Joule is one watt-second.
Or else you'll get erroneous results and become fooled or perhaps even ridiculed in the process.