Claimed OU circuit of Rosemary Ainslie

[PaulLowrance]

Being your not a *legit* researcher and never have been I can see why you have all the problems you do .... when a untrained monkey could possibly build this very small and well documented circuit ..... what actually is you problem ?? Jealousy, Ignorance or Stupidity ?? 

http://i276.photobucket.com/albums/kk15/fuzzytomcat/RA-COP17HeaterCircuit_01.jpg

LOL, why do you hurt yourself with such filth?  I don't have problems with my measurements, which BTW are far more difficult than the measurements you people need for this Ainslie device.

Jealous of what? You people are killing yourselves with your ridiculous measuring techniques?


Paul

[PaulLowrance]

Rosemary A. Ainslie gives her full name and the country she lives in, yet she refused to do a simple paypal exchange. It could be for 1 penny. Why not? Supposedly she's already provided her real name. If true, then anyone could find her without too much trouble. So why not add some credibility by doing a paypal exchange for $0.01? I seriously doubt "she's" even a female.

If so-called Rosemary A. Ainslie can prove her name then I would test the device. I would love to test it, but first I need some sincerity from "Rosemary Ainslie" because she's has not provide exact details to build her device. So lets get this over with. Just do the 1 cent paypal exchange, you get my name as well, and I'll spend 1 to 2 days testing this the correct way.


Paul

[PaulLowrance]

BTW, the above assumes that paypal is a legit way to prove ones identity. If not, then we'll need to use another method.

Paul

[poynt99]

I already went over this. You measure the *DC* current & voltage of the batteries. A simple low pass filter using a single op-amp will suffice. That's gives the power in. To measure the power out you measure how fast the components heat up, and then compare that to a control experiment. Very simple.

Paul

Paul,

I did essentially this. The only difference being; rather than measure the rate of temperature rise, I did a temperature rise above ambient measurement, which takes longer.

The power consumed was measured 3 different methods, including the DC one you specified in your post.

.99

[PaulLowrance]

Paul,

I did essentially this. The only difference being; rather than measure the rate of temperature rise, I did a temperature rise above ambient measurement, which takes longer.

The power consumed was measured 3 different methods, including the DC one you specified in your post.

.99

Is this what you're referring to -->

A confirmation of the results from Glen's test #5. I crunched only Hour 2 for the 2us and 20us runs. All powers calculated (for a complete perspective), not just POS.

2_2us_520V-02_10_11_09.xlr

POS = -3.206W
PIL = 112.3W
PIM = -116.5W
PIS = 0.95W

Final resistor temperature = 135ºF

2_20us_520V-02_10_11_09.xlr

POS = -4.046W
PIL = 100.8W
PIM = -105.7W
PIS = 0.87W

Final resistor temperature = 136ºF

Again, I ask Glen, Harvey, and Rose to explain the 100W PIL when clearly the load resistor is not dissipating this much power

It so, then where is the control experiment where you apply DC current through this load to see how much DC current is required to change the temperature to 136F? The control experiment will tell you how much power the load was producing.

Paul