Claimed OU circuit of Rosemary Ainslie

[poynt99]

Paul,

I'm using high-end 500MHz passive probes (model:5905-1RA) with only 8pF capacitance. I doubt they are having much influence on the circuit, at least to the degree I'm seeing.

All,

I will make my data available shortly so that others may compare the two tests that have only a slight grounding difference.

.99

[PaulLowrance]

I'm using high-end 500MHz passive probes (model:5905-1RA) with only 8pF capacitance. I doubt they are having much influence on the circuit, at least to the degree I'm seeing.

Also the load has capacitance. Mosfets generally have a lot of capacitance. Don't forget that the scope itself has capacitance.

And lets not even get into inductance, which will cause resonance, thereby giving the false impression of high current through the resistive element.

Those are some of the reasons I suggested from the start a very simple method that would take 1 to 2 days to do.

Anyhow, if you're going to measure the power with a scope, then short duration voltage spikes should be ignored. Maybe you could show the power figures that does not take spikes into consideration.

Paul

[PaulLowrance]

Here's the only recent photo in this thread I see, posted by poynt99:

http://www.overunity.com/index.php?action=dlattach;topic=7620.0;attach=38285;image

The green graph of voltage on the load shows a lot of oscillations. This kind of measuring techniques always requires tons of work digging deep to the find the actual voltage across the *resistance*.  The photos & descriptions of loads I've seen for the Rosie device seem large, and would be prone to ring and resonate.

Without measuring the heat production, it's easy to chase voltage ghosts.

Paul

[Rosemary Ainslie]

OK, downloaded (finally) Fuzzy's data from Test #3: "2us_520V_10_05_09_.xlr"
and crunched the data in my format:

POS = -1.2897W (power output from supply)
PIL = 96.6282W (power in to load resistor)
PIM = -98.7811W (power in to MOSFET)
PIS = 0.8632W (power in to shunt resistor)

Final load resistor temperature: 130ºF

Glen, Rose, all, please pay close attention to this one point:

Apply 97W (the measured PIL) of pure DC power to your Quantum resistor and measure the resistor's final temperature. If it is higher than 130ºF (and I am 100% certain it will be), then this 97W PIL measurement is erroneous.

And that is the point I have been stressing here; the data is not valid. Nor is my own, as my results are the same.

But don't take my word for it, do the 97W DC power test and prove it to yourself. As a check, input about 1.3W (or in your case about 4.5W) pure DC to the resistor and note the final temperature. Then ask yourselves, "How can the empirical results be argued?"

.99

Golly guys.  So many posts.  I'm not sure yet that I've backed up enough with this one.  But I do notice a marked difference in volume on this thread.  Such fun.

In any event I'm going to answer this first.  Poynt - That 97 watts on the resistor?  That's where we're all asking the question.  The data is not 'invalid' unless you want to confront some really hefty expertise.  It's the interpretation that needs to be done.  And from memory - I stand to be corrected here - that 4 odd watts was dissipated at no measurable loss from the supply.

Which makes it COP - OU - take your pick - but somewhere up there.  At least?   

[PaulLowrance]

Golly guys.  So many posts.  I'm not sure yet that I've backed up enough with this one.  But I do notice a marked difference in volume on this thread.  Such fun.

This is nothing compared to the attention that the mylow case received. Maybe that's your goal.