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Overunity Machines Forum



Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

Started by Pirate88179, June 27, 2009, 04:41:28 AM

Previous topic - Next topic

0 Members and 230 Guests are viewing this topic.

verpies

Quote from: baroutologos on January 14, 2013, 02:09:08 PM
Long time i have to follow this thread.. but out of habit i do from times to times. I must say, i admire your tenacity, your clear reasoning and your will to investigate the "Kapanadze secret".
Thanks, but I am not doing this to investigate "Kapanadze's secret".  I just feel that sometimes I can contribute my knowledge and experience to some promising users of this forum.
When I was learning this stuff, I also had people that were willing to take their time to explain things to me.
Sometimes, even today I learn sth useful myself.  e.g. lately from TinselKoala.

Sometimes, I simply cannot stand reading misconceptions being perpetuated or the same mistakes being repeated over and over and I set out to correct them.
Most of the time I encounter hard headed people who are immune to logical thinking and are full of esoterica and hero worship. If I detect those characteristics, I usually give up on them.

Quote from: baroutologos on January 14, 2013, 02:09:08 PM
The more distancing myself from all that, the more i see Kapanadze as a magician and lying individual claiming something he obviously do not possess and cannot even describe in scientific as well as practical terms.
That is very likely. However I feel it is the duty of the scientists to expose magician's tricks just like Wattsup did recently with his Kapanadze's video analysis.
I respect Zeitmachine's tenacity in providing logical and mostly unemotional opposition to Wattsup's conclusions, too.

verpies

Quote from: leo48 on January 14, 2013, 11:01:57 AM
> On tri-phase system the power = V * I * 1.73

At the beginning of this discourse was talking about a three-phase sinusoidal
industrial at 50 or 60 Hz and voltages according to the local grid.
OK, the industrial power grid in Europe provides 650VP-P sinusoidal voltage at 50Hz.

The 50Hz means, that the voltage between the neutral wire and any other wire is changing 50 times per second from +325V to -325V according to the +325sin(t) function.  In other words, the voltage is not constant in time.
So what voltage does the "V" mean in your equation if voltage in European industrial grid is not constant?  +325V, +100V, +66V, +12V, 0V, -12V, +66V, +100V, -325V or something else...?
What about the "I", what does it represent in this equation ?

captainkt

@Verpies, just quickly the grid in UK is 415 volt 50 HZ.

Regards
Keith

leo48

Ok

Mr Verpies necessary to explain the grid as a function of energy

P=V*I*1.73

P=effective power              = Watt
V=effective voltage            = Volt   -- Measured between two phases
I=Intensity of current          = Ampere --Measured on each phase

1.73= root squared of 3  For the three-phase system

Any neutral wire and zero voltage with respect to ground

I hope it is clear how to measure the variables in the grid industry  :)

Leo48
Every problem has always at least two solutions simply find
The strength of the strong is the ability to navigate struggles with eye serene

verpies

Quote from: captainkt on January 15, 2013, 04:00:47 AM
@Verpies, just quickly the grid in UK is 415 volt 50 HZ.
Really?  415V from peak-to-peak of the sine wave ?
Measured between the neutral and any of the other three wires or between some other wires ?

P.S.
I am disregarding the ground wire for now.