Selfrunning Free Energy devices up to 5 KW from Tariel Kapanadze

[wattsup]

Hi Zeitmaschine,

Imagine that all the radio, tv and any other RF, HF transmitter could be switched off at a given moment in every country and you would be left with an enviroment fully free from any man-made EM sources. Do you think that the circuit shown in the video you gave a link ( https://www.youtube.com/watch?v=EYYysBEwA6w ) would still produce the shown 13 V or so DC output?

My answer is no, the meter would read zero because the electric 'noise' or static noise (not man-made) always present in the air has so small amplitude the rectifier diodes used in that circuit simply cannot detect. When a stormy weather is coming the electric 'activity' in the air increases and the overall electric 'noise' amplitude increases manyfold, (ionization), the diodes with their 0.6 V (Si) or 0.1 V (Ge) thresholds will be able to detect them and steer them into those capacitors.

There are radiations coming from space of course like from quasars, stars, suns etc but it is extremely unlikely that these radiations could be detected with the diode types used in those schematics. You need to devise a totaly new method to capture such radiations efficiently, you need to know the frequency ranges involved (xray, visible light etc).


  gyulasun wrote: 
Zeitmaschine answered:
Remember, you used your oscilloscope to see the induced voltage across the coil coupled to the parallel LC resonant tank circuit, so you had only the high impedance probe as the load, this did not reflect back to the source. Just try to apply useful loads instead of the scope probe and see what happens in that setup. On "no problem" I meant again that your shown setup was explainable again by normal science (unfortunately), and whenever something is explainable by known science it involves conversation of energy in most (but not all) cases.

I am pleased you think you are very close to the exit of the labyrinth, please keep it up.
Greetings,  Gyula

@gyulasun

You never really know. It could produce more with zero man-made "interference" leaving the device to fully respond to the Earth rhythm or Shewman frequency that would then be perfectly attuned to a single real "Earth pulse", rather then being bombarded by so many other influences that are more probably causing a high degree of internal cancellation. As you can see how the diodes are arranged to work in additive mode via any input coming in regardless of the off phase nature of such inputs, but it could still cause a great deal of cancellation. Obviously such radiant circuits have to deal with the complete influences and so we have to realize that those influences are not all additive but also "subtractive" and hence what we see as final output is the basic end result of a major tug or war.

wattsup

[Zeitmaschine]

My answer is no, the meter would read zero because the electric 'noise' or static noise (not man-made) always present in the air has so small amplitude the rectifier diodes used in that circuit simply cannot detect. When a stormy weather is coming the electric 'activity' in the air increases

This website gives me a value of the Earth's electric field of 100 to 150 volts per meter on a sunny day and 15 to 20 KV (!) per meter on a stormy day. Then why should an antenna not be able to catch that electricity? What's wrong? Maybe we should omit the small capacitors (shorting it).

Remember, you used your oscilloscope to see the induced voltage across the coil coupled to the parallel LC resonant tank circuit, so you had only the high impedance probe as the load, this did not reflect back to the source.

The LC circuit is the load. If it would not dissipate energy then it would oscillate forever. We have hence a load and a power source that not cares about that load. That's good (for a start).

I am pleased you think you are very close to the exit of the labyrinth, please keep it up.

At least I think I'm close to the end-wall of the labyrinth. Now I'm looking for the exit. If I can't find it, then I'm stuck and have to call a rescue team since there is no point in going back into the labyrinth again.

[gyulasun]

This website gives me a value of the Earth's electric field of 100 to 150 volts per meter on a sunny day and 15 to 20 KV (!) per meter on a stormy day. Then why should an antenna not be able to catch that electricity? What's wrong? Maybe we should omit the small capacitors (shorting it).

Yes, I am aware of that V/m field values.  Trying to exploit atmospheric electricity (voltage source) involves high risk: the possibility of lightning strikes because you would need to use long and highly elevated conductors. Collecting high voltage would be a must because that would be the only way to increase the output power from such 'tapping the air' setups. This is because unfortunately the output current is very low by default due to the very high inner resistance of such voltage sources (air is basically an insulator up to a known breakdown voltage of course).
There are old patents on tapping the atmospheric electricity, using kites or ballons for pulling up and holding long wires in air, preferably spanned horizontally too, to achive conductor layers one above the other. If such setups can indeed provide useful amount of power, that would indeed be free. However, safety first, there is high risk of lightning strikes alongside the downcoming wires, depending on also the geographical locations.

The LC circuit is the load. If it would not dissipate energy then it would oscillate forever. We have hence a load and a power source that not cares about that load. That's good (for a start).

Yes it would be good for a start. If you still have that parallel LC tank setup at 50 Hz, and will have some time, please try to load the output coil with a just some Watt power lamp and see whether the DC input of the inverter starts changing or not when you can see a lamp is just bright (not LED lamp but a 12V, some Watt power lamp).  You will have correct answer then.

Gyula

[Zeitmaschine]

If such setups can indeed provide useful amount of power, that would indeed be free. However, safety first

That's a step forward. If we discard safety then we have free energy.

please try to load the output coil with a just some Watt power lamp and see whether the DC input of the inverter starts changing or not

I prefer the other way round: First we need a measurable ground current, then we can connect a load to the system. The ground current is the key to free electric energy. Looks like the main component we need for this is a 3-phase transformer in some special configuration - at least for a start.

Electric current is a measure of the flow of charged particles past some point.

Yes, OK. But I can find still no answer to my question where the charges of theses particles are initially coming from. Space is the best explanation so far.

[Hoppy]

I prefer the other way round: First we need a measurable ground current, then we can connect a load to the system. The ground current is the key to free electric energy. Looks like the main component we need for this is a 3-phase transformer in some special configuration - at least for a start.

How much ground current do you reckon would be needed to run Kapanadze's 2KW electric fire?